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Burka [1]
3 years ago
12

An elevator ascends,or goes up,at a rate of 750 feet per minute.is the height to which the elevator ascend proportional to the n

umber of minutes it takes to get there
Mathematics
1 answer:
Sliva [168]3 years ago
7 0
C=480
solve

480=24n+35
minus 35 both sides
445=24n
divide both sides by 24
18.541666666666666666666666666667=n

<span>so about 18 cakes</span>
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Help can someone help me find the value of ClX Y and Z I would appreciate it luvvs ;) ♡​
Stolb23 [73]

\\ \sf\longmapsto 9x+46=35

\\ \sf\longmapsto 9x=35-46

\\ \sf\longmapsto 9x=-11

\\ \sf\longmapsto x=\dfrac{-11}{9}

6 0
3 years ago
The drama teacher decreased the length of a play from 90 minutes to 60 minutes. What was the percent decrease in the length of t
algol13

Answer:

It was a 33% decrease

Step-by-step explanation:

90 minutes - 60 minutes = 30 minutes

30/90= .333333333333

4 0
3 years ago
Round 9.55555 to the nearest hundredths
Paraphin [41]
When you round 9.55555 to the nearest hundredth you would get 9.56 which you would then round to 10
3 0
3 years ago
Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die
Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

6 0
3 years ago
Please answer i will give brainlest
Vitek1552 [10]

Answer:

here ya go

Step-by-step explanation:

1. 20

2.1793

3. 1943

im noy to sure on the bottom ones but use ctrl f in the notes you use for this or something and type in the "transacted" or something in the question and your answer should pop up

7 0
2 years ago
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