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Tanzania [10]
3 years ago
9

What is the square root of 59

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0

the square root of 59 is about 7.68114575.
Sholpan [36]3 years ago
8 0
The square root of 59 would be 7.68
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954 to the nearest hundred
Zepler [3.9K]

Answer:

1000

Step-by-step explanation:

You are solving for the hundreds place. Find the tens place. It is a 5. Note that when the digit is 5 & up, round up. If 4 and down, round down.

954 rounded to the nearest hundreds place is 1000.

~

6 0
3 years ago
What is 20,484,163 in word form
sweet-ann [11.9K]
In word form it would be:
Twenty million, four hundred eighty-four thousand, one hundred sixty-three

In expanded form it would be:
20,484,163
<span>= 20,000,000 + 400,000 + 80,000 + 4,000 + 100 + 60 + 3

</span>Hope I Helped!!

6 0
3 years ago
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In a mathematics class, half of the students scored 79 on an achievement test. With the exception of a few students
Yakvenalex [24]
In this situation, you have:
The mode is 79 (that’s the most common number).
The median is 78.5 (the middle value or the average of the two middle values, since there is an even number of test scores).
The mean is less than both of those, as it was brought down by the few scores of 49.

The means the mean will be less than median.

Answer: C
3 0
3 years ago
Which of the following points would be a solution to this system of linear inequalities? ​
pychu [463]

Let's plug in both x and y values in the equation and check if the inequality is true...

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

(4,1) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 4 and y as 1

1 \leqslant 4 + 1 \\ 1 <  -  \frac{4}{2}  - 1

0  \leqslant  4 + 1 \\ 1 <  - 2 - 1

0 \leqslant 5 \\ 1 <  - 3

  • <em>This is not a solution because both are not true, Only one equation is giving true as answer which is not correct!~</em>

\purple{ \rule{300pt}{3pt}}

(0, - 3) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 0 and y as -3

- 3 \leqslant 0 + 1 \\  - 3 <  -  \frac{0}{2}  - 1

- 3 \leqslant 1 \\  - 3 <  - 0 - 1

- 3 \leqslant 1 \\  - 3 <  - 1

  • <em>This is a solution because both are true, </em><em>Both the </em><em>equations</em><em> </em><em>are</em><em> </em><em>true</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>ordered</em><em> </em><em>pair</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>solution</em><em>!</em><em>~</em>

<u>Thus</u><u>,</u><u> </u><u>Option</u><u> </u><u>B</u><u> </u><u>(</u><u>0</u><u>,</u><u>-</u><u>3</u><u>)</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>correct</u><u> </u><u>choice</u><u>.</u><u>.</u><u>.</u><u>.</u>

6 0
3 years ago
What is the measure of ∠H?
jek_recluse [69]
B. 73
360-102-138-47=73
5 0
3 years ago
Read 2 more answers
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