1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Answer:
14.02
Step-by-step explanation:
You'd have to write equations for the price per month for each club.
Let x equal the number of months of membership, and y equal the total cost.
Club A's is y
=
24x
+
21.50 and Club B's is y
=
17.25
x
+
41.00 Because we know that the prices, y
, would be equal, we can set the two equations equal to each other.
24x
+
21.50
=17.25
x+
41.00
subtract 21.50 both sides
. We can now solve for x by isolating the variable.
24x=17.25x+19.5
divide 17.25x
1.39x=19.5
divide 1.39 both sides
x=14.02
After five months, the total cost would be the same.
Answer:
39. 29
36. 50
33. 7
30. 33
Step-by-step explanation:
39. According to the Order of Operations, in this case, Subtraction & Addition are evaluated after Division & Multiplication:

36. Evaluate everything since everything is wrapped in parentheses:

33. Evaluate everything inside of parentheses FIRST:

I am joyous to assist you anytime.
Answer:
37
Step-by-step explanation:
6x+y
Let x = 5 and y = 7
6*5+ 7
Multiply
30 +7
Add
37
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