Based on the CPCTC theorem, the congruences that are true about the given triangles are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
<h3>What is the CPCTC Theorem?</h3>
According to the CPCTC theorem states that if two triangles are congruent to each other, then, all their corresponding parts will be congruent to each other.
Given that triangles JKL and RST are congruent to each other, therefore:
∠J ≅ ∠R
∠K ≅ ∠S
∠L ≅ ∠T
JK ≅ RS
KL ≅ ST
JL ≅ RT
Therefore, the congruences that would be true by CPCTC are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
Learn more about the CPCTC theorem on:
brainly.com/question/14706064
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Answer:
54,706 > 45,802
Step-by-step explanation:
Well, as you know, the > symbol means that one number has a greater value than another. For example, 2 > 1. The way we can find that out is using subtraction. Take 54,706 - 45,802, and if that number is positive, then the first number is greater than the other.
54,706 - 45,802 = 8,904
8,904 is a positive.
Therefore, 54,706 > 45,802.
Your answer is C . good luck.
Well there are 33 total people in the class, so the chance of drawing a boy's name is
Answer:
The solution of the Given matrix
( x₁ , x ₂ ) = ( - 5 , 4 )
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given equations are x₁+4 x₂ = 11 ...(i)
2 x₁ + 7 x₂= 18 ...(ii)
The matrix form
A X = B
![\left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C2%267%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<u>Step(ii):-</u>
The Augmented Matrix form is
![[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]](https://tex.z-dn.net/?f=%5BAB%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%2611%5C%5C2%267%2618%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Apply Row operations, R₂ → R₂-2 R₁
![[AB] = \left[\begin{array}{ccc}1&4&11\\0&-1&-4\\\end{array}\right]](https://tex.z-dn.net/?f=%5BAB%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%2611%5C%5C0%26-1%26-4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The matrix form
![\left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%5C%5C-4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The equations are
x₁ + 4 x₂ = 11 ...(a)
- x ₂ = - 4
x ₂ = 4
Substitute x ₂ = 4 in equation (a)
x₁ + 4 x₂ = 11
x₁ = 11 - 16
x₁ = -5
<u>Final answer</u>:-
The solution of the Given matrix
( x₁ , x ₂ ) = ( - 5 , 4 )
