Answer:
Yes, that is correct.
Step-by-step explanation:
Let's start with the order of operations.
12 x 12 = 10
Are there any brackets? No.
Exponents? No.
Multiplication or division? Yes!
12 x 12 = 144
144 + 10
Addition or Subtraction? Yes!
144 + 10 = 154
So, 154 is right!
We need to assign a value for x to check the possible values of y.
1st inequality: y < -0.75x
X = - 1 ; y < -0.75(-1) ; y < 0.75 possible coordinate (-1,0.75) LOCATED AT THE 2ND QUADRANT
X = 0 ; y < -0.75(0) ; y < 0 possible coordinate (0,0) ORIGIN
X = 1 ; y < -0.75(1) ; y < -0.75 possible coordinate (1,-0.75) LOCATED AT THE 4TH QUADRANT
2nd inequality: y < 3x -2
X = -1 ; y < 3(-1) – 2 ; y < -5 possible coordinate (-1,-5) LOCATED AT THE 4TH QUADRANT
X = 0 ; y < 3(0) – 2 ; y < -2 possible coordinate (0,-2) LOCATED AT THE 4TH QUADRANT
X = 1 ; y < 3(1) – 2 ; y <<span> 1 possible coordinate (1,1) LOCATED AT THE 1ST QUADRANT
The actual solution to the system lies on the 4TH QUADRANT.
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It would be negative.
Absolute value is basically asking how far away something is from 0.
So say you had a number, 7. 7's distance from 0 is 7, so it would still be 7.
However, when absolute value really plays in is negative numbers. If you had -7, the distance from 0 would still be 7. It wouldn't be -7, so the absolute value of -7 would be 7.
And a negative version of a number is always less than the positive number.
Hope this helped!
To get the resultant magnitude and direction of the forces we need to separate the force into its x and y components. For the x components it is the sum of 2000cos(30) and 900cos(45), which is 2368.4469 N. For the y components it will be the sum of 2000sin(30) and -900sin(45), the value for the second force is negative because it is pointing downwards, their sum would be 363.6038 N. The magnitude for the resultant force can be determined using the pythagorean theorem R=sqrt(2368.4469^2 + 363.6038^2) while its direction is found using tan^-1(363.6038/2368.4469). The final answer would be 2396.1946 N with an angle of 8.7279 degrees from the right side of x axis.
