Answer:down there
Step-by-step explanation:
Start with 60 fliers
post 1/4 of fliers so 60*.25=15
60-15=45 left
post 1/5 of remaining so 45*.20=9
45-9=36 left
Have a great day!
The answers would be 49,51,and53!
We know that
Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19
the answer Part a) is 19
Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10
we know that
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34
the answer Part b) is -34
Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48
the answer Part c) is 48</span>
First point (0,1)
x=0, -3*0+2y=2, y=1
second point (2,4)
-3x+2y=2
x=2, -3*2+2y=2, -6+2y=2, 2y=8, y=4
third point (-2, -2)
x=-2, -3*(-2)+2y=2, 6+2y=2, 2y=-4, y=-2
Answer:
8192
Step-by-step explanation:
In this sequence each term is the product of the two previous terms. Therefore the next term would be the product of 32 and 256.
32 × 256 = 8192
Therefore the final term is 8192.
