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almond37 [142]
3 years ago
10

The gas pressure in an aerosol can is 1.8 atm at 25°c. if the gas is an ideal gas, what pressure would develop in the can if it

were heated to 475°c
Chemistry
1 answer:
Ratling [72]3 years ago
3 0
For ideal gases at constant volume, you can use the law of Gay - Lussac:

P / T = constant => P1 / T1 = P2 / T2

=> P2 = T2 * P1 / T1

And remember you have to use absolute scale of temperature.

T1 = 25 + 273.15 = 298.15 K

T2 = 475 + 273.15 = 748.15 K

=> P2 = 748.15 K * 1.8 atm / 298.15 K = 4.5 atm

Answer: 4.5 atm
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k0ka [10]

Answer:

The concentration of the HNO3 solution is 0.150 M

Explanation:

<u>Step 1:</u> Data given

Volume of the unknown HNO3 sample = 0.120 L

Volume of the 0.200 M Ba(OH)2 = 45.1 mL

<u>Step 2:</u> The balanced equation

2HNO3 + Ba(OH)2 ⟶ Ba(NO3)2 + 2H2O

<u>Step 3:</u> Calculate moles Ba(OH)2

moles Ba(OH)2 = molarity * volume

moles Ba(OH)2 = 0.200 M * 0.0451 L

moles Ba(OH)2 = 0.00902 moles

<u>Step 4:</u> Calculate moles of HNO3

For 1 mole of Ba(OH)2 we need 2 moles of HNO3

For 0.00902 moles of Ba(OH)2 we need 2*0.00902 = 0.01804 moles

<u>Step 5</u>: Calculate molarity of HNO3

molarity = moles / volume

molarity = 0.01804 / 0.120 L

Molarity = 0.150 M HNO3

The concentration of the HNO3 solution is 0.150 M

6 0
3 years ago
At 500K, the equilibrium constant for the reaction N2O4D2NO2 is 1.5 x 10^3. What is the equilibrium constant for the reaction: 6
Veronika [31]

Answer:

K = 2.96x10⁻¹⁰

Explanation:

Based on the initial reaction:

N2O4 ⇄ 2NO2; K = 1.5x10³

Using Hess's law, we can multiply this reaction changing K:

3 times this reaction:

3N2O4 ⇄ 6NO2; K = (1.5x10³)³ =3.375x10⁹

The inverse reaction has a K of:

6NO2 ⇄ 3N2O4 K = 1/3.375x10⁹;

<h3>K = 2.96x10⁻¹⁰</h3>

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3 years ago
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vovikov84 [41]

Answer:

yes I do think they mean the same thing

Explanation:

150 grams and 150 grams is the same thing and adding 0 to the end of a decimal does not change its value, you could even put 150.0000000 grams and it would still be equivalent to the other numbers

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Luba_88 [7]
I found this on google

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