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3 years ago

Suppose that the duration of a particular type of criminal trial is known to be

Mathematics

1 answer:

abruzzese [7]3 years ago

8 0

Answer:

c.) if the one of the trails is randomly chosen, find the probability that it lasted at least 24 days

Step-by-step explanation:

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A student conducted a poll of 100 internet users and found the average time spent online per day was 2 hours. The student descri

n200080 [17]

I believe it's B or A Sample.

3 0

3 years ago

Read 2 more answers

What fraction of 42 g is 7000 mg

Vsevolod [243]

Answer:

3/500

Step-by-step explanation:

42/7000 simplified is 3/500 or in decimal form it's 0.006

4 0

3 years ago

Question 14. A carousel makes one complete revolution every 75 seconds. Levi sits on the carousel 4 feet from its center. If the

garik1379 [7]

Answer:

The correct option is;

H. 32·π

Step-by-step explanation:

The given information are;

The time duration for one complete revolution = 75 seconds

The distance from the center of the carousel where Levi sits = 4 feet

The time length of a carousel ride = 5 minutes

Therefore, the number of complete revolutions, n, in a carousel ride of 5 minutes is given by n = (The time length of a carousel ride)/(The time duration for one complete revolution)

n = (5 minutes)/(75 seconds) = (5×60 seconds/minute)/(75 seconds)

n = (300 s)/(75 s) = 4

The number of complete revolutions - 4

The distance of 4 complete turns from where Levi seats = 4 ×circumference of circle of Levi's motion

∴ The distance of 4 complete turns from where Levi seats = 4 × 2 × π × 4 = 32·π.

3 0

3 years ago

13) The dance committee is planning the winter dance. The cost of a DJ is $250. The cost to attend the dance

Sergio039 [100]

90 kids
If the DJ is 250 and the pizza is 200 that is $450 altogether
Now if you divide 450 by 5 (the cost to attend the dance) you get 90!
I hope this helped

3 0

3 years ago

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Please answer the question below (ABOUT VECTORS AND MAGNITUDE)

coldgirl [10]

(a) v appears to have a fixed direction along the positive x-axis. If ||u|| = 150 N, ||v|| = 220 N, then when θ = 30°, you have

u = (150 N) (cos(30°) i + sin(30°) j ) ≈ (129.904 i + 75 j ) N

v = (220 N) (cos(0°) i + sin(0°) j ) = (220 i ) N

(i and j are the unit vectors in the positive x and y directions)

and their sum is

u + v ≈ (349.904 i + 75 j ) N

with magnitude

||u + v|| ≈ √((349.904)² + (75)²) N ≈ 357.851 N ≈ 357.9 N

and at angle φ made with the positive x-axis such that

tan(φ) ≈ (75 N) / (349.904 N) → φ ≈ 12.098° ≈ 12.1°

(b) Letting θ vary from 0° to 180° would make v a function of θ :

u = (150 N) (cos(θ) i + sin(θ) j ) = (150 cos(θ) i + 150 sin(θ) j ) N

Then

u + v = ((220 + 150 cos(θ)) i + (150 sin(θ)) j ) N

→ M = ||u + v|| = √((220 + 150 cos(θ))² + (150 sin(θ))²) N

M = √(48,400 + 66,000 cos(θ) + 22,500 cos²(θ) + 22,500 sin²(θ)) N

M = 10 √(709 + 660 cos(θ)) N

(c) As a function of θ, u + v makes an angle α with the positive x-axis such that

tan(α) = (150 sin(θ) / (220 + 150 cos(θ))

→ α = tan⁻¹((15 sin(θ) / (22 + 15 cos(θ)))

(d) Filling in the table is just a matter of evaluating M and α for each of the given angles θ. For example, when θ = 0°,

M = 10 √(709 + 660 cos(0°)) N = 370 N

α = tan⁻¹((15 sin(0°) / (22 + 15 cos(0°))) = 0°

When θ = 30°, you get the same result as in part (a).

When θ = 60°,

M = 10 √(709 + 660 cos(60°)) N ≈ 323.3 N

α = tan⁻¹((15 sin(60°) / (22 + 15 cos(60°))) = 23.8°

and so on.

4 0

3 years ago