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3 years ago

What is the domain of the square root function graphed below?

Mathematics

1 answer:

Xelga [282]3 years ago

3 0

Answer:

Option (4)

Step-by-step explanation:

Domain of a function is a set of x-values (Input values) of the function.

For the given graph of square root function,

x - values starts from x = 0 and tends to x = ∞

Therefore, domain of the function will be,

x ≥ 0

Option (4) will be the correct option.

You might be interested in

Write an algebraic expression or equation 5 times the sum of three and a number

maksim [4K]

Answer: 3+5x

Step-by-step explanation:

Simply and Think Hard

6 0

4 years ago

Which is greater: An angle showing a turn through 1/6 of a circle or an angle showing to turn through 1/5 of a circle explain yo

Rashid [163]

Answer:

An angle showing a turn through 1/5 of a circle is greater

Step-by-step explanation:

we know that

A complete circle represent $360\°$

An angle showing a turn through 1/6 of a circle is

$(360\°)*(\frac{1}{6})=60\°$

An angle showing a turn through 1/5 of a circle is

$(360\°)*(\frac{1}{5})=72\°$

therefore

An angle showing a turn through 1/5 of a circle is greater

4 0

3 years ago

Solve.

Ksenya-84 [330]

Solve.

x² + 4x + 4 = 18

A x=−4±3√ 2

B x=2±3√ 2

C x=4±9√ 2

D x=−2±3√2

 $x^2 + 4x + 4 = 18 \\ \\ x^2+4x+4-18= 0 \\ \\ x^2+4x-14=0 \\ \\ x_1_y_2= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{16-(-56)} }{2} \\ \\ \\ x_1_y_2= \dfrac{-4\pm \sqrt{72} }{2} \\ \\ \\ x_1= \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2= \dfrac{-4+ \sqrt{72} }{2}\\ \\ \\ x_1= \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2= \dfrac{-4- \sqrt{2^3*3^2} }{2}$

 $x_1= \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 2*3\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4- 6\sqrt{2} }{2} \\ \\ \\ x_1= \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2= \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\ \\ \\ x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad x_2= -2- 3\sqrt{2} \\ \\ \\ \boxed{x= -2\pm 3\sqrt{2} } \to D)$

7 0

4 years ago

Read 2 more answers

Write an expression in simplest form for the perimeter of the figure

dsp73

Answer: 11x + 5y

Step-by-step explanation:

FInd the perimeter by adding all the expressions together.

4x + 5x + 2.8y + 2x + 2.2y Combine like terms

(4x + 5x + 2x) + (2.8y + 2.2y)

11x + 5y

5 0