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Amanda [17]
3 years ago
14

How many solutions does the system of equation have?

Mathematics
2 answers:
serious [3.7K]3 years ago
8 0
We can determine the number of solutions from the slope intercept form of the equations.

Slope intercept form of equation 1 is:

y=- \frac{1}{4}x+3/4

Slope intercept form of second equation is:

y=- \frac{1}{4}x+ \frac{9}{12} \\  \\ 
y=  - \frac{1}{4}x+ \frac{3}{4}

The slope and the y-intercept of both equations are the same. This means, the two lines are lying over each other and hence they infinite number of solutions.

So, the correct answer is option C
miss Akunina [59]3 years ago
6 0
The equation no solution. This is because the lines are parallel.
The general equaltion of a line is,

Y=mX+c, where m is the gradient and c is the Y-intercept.

For the first equation,
<span>4x + 16y = 12
16y=-4x+12
y=(-1/4)x+12/16
gradient =-1/4</span>

For the second equation, Y = (-1/4)x +9/12,  the gradient = -1/4
 If the gradients are equation then, the lines do not meet hence no solutions.

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Which is the best definition of a conic section
slega [8]
Are there options? Otherwise the definition is: <span>a figure formed by the intersection of a plane and a right circular cone. Depending on the angle of the plane with respect to the cone, a conic section may be a circle, an ellipse, a parabola, or a hyperbola.
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7 0
3 years ago
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Ling is using fraction strips to add 2/3 and 7/12's The sum is one whole Plus how many twelves?
Leno4ka [110]

Hello from MrBillDoesMath!

Answer:

3/12   (aka 1/4)


Discussion:

2/3 + 7/12   = 8/12 + 7/12                     => as 2/3  = (2*4)/(3*4)   = 8/12      

                  = 15/12

                  = 1 + 3/12



Thank you,

MrB

5 0
4 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
4 years ago
I have to be awake at 5am and it’s about to be 12am so can someone please help me with this 7th grade math homework
finlep [7]

Step-by-step explanation:

Divide the denominator by the numerator to find the percentage

5 0
4 years ago
Simplify
amm1812
3ab * 2ac = 6a^2bc
3ab * 3bc = 9ab^2c
= 6a^2bc + 9ab^2c

So the answer is D
8 0
4 years ago
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