Answer:
2 1/3 minutes
Step-by-step explanation:
4/3 minute = 80 seconds
80/4 (from 4/7) =
20 seconds per 1/7
20 * 7 = 140
140 to minutes = 2minutes and 20 sec or 2 1/3 minutes
The correct question is:
Determine whether the given function is a solution to the given differential equation. y = cosx + x^8; d²y/dx² + y = x^8 + 56x^6
Step-by-step explanation:
Given the differential equation
d²y/dx² + y = x^8 + 56x^6.
Suppose y = cosx + x^8 is a solution, then differentiating y twice, and adding it to itself, must give the value on the right hand side of the differential equation.
Let us differentiate y twice
y = cosx + x^8
dy/dx = -sinx + 8x^7
d²y/dx² = -cosx + 56x^6
Now,
d²y/dx² + y = -cosx + 56x^6 + cosx + x^8
= 56x^6 + x^8
Therefore,
d²y/dx² + y = x^8 + 56x^6
Which shows that y = cosx + x^8 is a solution to the differential equation.
22.5/5 = 4.5
For every 4.5 minute, she runs 5 km
Answer:
To be done in time, he would need to solve 6 questions per day on the days that he is not on trip
Step-by-step explanation:
If he solves the problems 5 per day, the total number of days that would be required to finish solving the problem would be 120/5 = 24 days
Now, he has 4 free days which would be for a family trip. The number of questions that he would miss during those trip days will be 4 * 5 = 20 questions
Now since he wants to still finish on time, what is needed to be done is to share the 20 left overs amongst the 20 days which he has to work
This makes a total of 1 question per day
Adding this to the 5 questions per day he has before will be = 6 questions per day
Answer:

Step-by-step explanation:
We are given the following equation:

We have to convert it into polar form.
We put

Putting values, we get:

is the required polar form.