Is there anyone that is willing to help me with my math assignment through via email

ss7ja [257]

Answer:

<h2>no real solution</h2>

Step-by-step explanation:

$-3x^2-4x-4=0\qquad\text{change the signs}\\\\3x^2+4x+4=0\\\\\text{use the quadratic formula:}\\\\\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\text{We have}\ a=3,\ b=4,\ c=4.\\\\\text{Substitute:}\\\\b^2-4ac=4^2-4(3)(4)=16-48=-32$

8 0

4 years ago

he price of a pair of shoes increases from $68 to $77. What is the percent increase to the nearest percent?

tekilochka [14]

Answer:

an increase of 12%

Step-by-step explanation:

68 divided by 77 is 0.88 approximately

100-88 is 12

Tip:

do this for increase and decrease in percentage question

divide small number by big number, and subtract the quotient from 100

8 0

3 years ago

Read 2 more answers

A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 125 is selected and is used to estimate

Mrrafil [7]

Answer:

a: 0.8884

b: 0.9934

Step-by-step explanation:

We have µ = 300 and σ = 70. The sample size, n = 125.

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.8884

Next we want the probability of the sample mean to be within 17 units of the population mean, so we want the values from 283 to 317. We want to find

P(283 < x < 317)

We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.

We have P(283 < x < 317) = 0.9934

5 0

3 years ago

a bag contains 10 white gold balls and 6 striped golf balls. a golfer wants to add 112 golf balls to the bag. he wants the ratio

wolverine [178]

Answer:70 white golf balls and 42 striped golf balls

Step-by-step explanation:

First we find the ratio of white to striped balls

White golf balls = 10

Striped golf balls = 6

Ratio = 10/6 = 5/3

We are told a golfer wants to add extra 112 balls to the already 16 balls

And the ratio after adding 112 balls must stay the same

First we label the extra golf balls to be added x and y

x = white golf balls

y = striped golf balls

So since we know the 112 balls added is a combination of the extra white golf balls and striped golf balls, we create an equation for that, labelling it (1)

x + y = 112 (1)

And we are told that after putting these extra balls the ratio must remain the same, which is 5/3

which will be (10 white balls + x) divided by (6 striped ball + y) will be equals to 5/3

So we create another equation for this, labelling it (2)

(10+x)/(6+y) = 5/3 (2)

So we have two simultaneous equations

We pick (1)

x + y = 112

We either make x or y the subject of formula, I choose to make x the subject of formula, we label the equation (3)

take y to the other side, causing it to change to -y

x = 112 - y (3)

We then work with (2)

(10+x)/(6+y) = 5/3

We cross multiply

3(10+x) = 5(6+y)

We open the brackets

Making the equation simplified and labelling it (4)

30 +3x = 30 + 5y

Collect like terms

3x -5y = 30-30

3x -5y = 0 (4)

Remember from (3) we know that

x = 112 -y

So we put (3) in (4)

3(112 - y) - 5y = 0

Open bracket

336 -3y -5y =0

336 -8y = 0

Transfer -8y to the other side, changing to +8y

336 = 8y

Divide both sides by 8

336/8 = y

42 = y

y = 42

from (3) we know that x equals 112 - y

So we put y = 42 in (3)

x = 112 - y

x = 112 -42 = 70

x = 70

So therefore number of white golfs balls and striped golfs balls to be added to keep the same ratio is 70 and 42 respectively

4 0

3 years ago

How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Not

Jet001 [13]

If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are

$\dbinom52=\dfrac{5!}{2!(5-2)!}=10$

ways of picking the vowels, and

$\dbinom{20}2=\dfrac{20!}{2!(20-2)!}=190$

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is

$4!\dbinom52\dbinom{20}2=\boxed{45,600}$

Keep in mind that this means words like TRIES and TIRES are treated as different.

8 0

3 years ago

Is there anyone that is willing to help me with my math assignment through via email​

Is there anyone that is willing to help me with my math assignment through via email