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givi [52]
1 year ago
13

The ratio of hydrogen atoms to oxygen atoms in water is 2:1. If an amount of water contains 341 trillion atoms of oxygen. How ma

ny hydrogen atoms are there?
Mathematics
1 answer:
saw5 [17]1 year ago
8 0

Answer:

There will be 681 trillion atoms of hydrogen

Step-by-step explanation:

2:1 is the same as 2/1 so all you need to do is multiply 2 to the oxygen

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Solve the equation for the variable numerically using a
tangare [24]

Answer:

x= 12

Step-by-step explanation

3x+8=44

subtract 8 from both sides:  3x+8= 44

                                                     -8    -8

3x=36

then divide by 3 on both sides

3x=36

3    3

which leaves : x=12

my explaining is horrible but i hope this helps

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2 years ago
(multiple choice) How is e-mail different from other types of communication?
Dmitry_Shevchenko [17]

Answer: You can't hear the tone of voice or get clues from body language.

Step-by-step explanation:

When sending emails, the sender and the recipient communicate through a screen, thus each person is unable to see the other when conversing or hear the inflections or emphasis of voice in the message, although we can always attempt to interpret tone. Email allows you to store emails in the inbox or archive and access sent messages, but email lacks the ability to intimately understand specifics such as tone of voice or body language.

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3 years ago
1+2-3+4+5-6+7+8-9...+97+98-99
zaharov [31]

Answer:

  1584

Step-by-step explanation:

The sum of this sequence can be found a number of ways. One way is to recast it as the series whose terms are groups of three terms of the given series.

__

<h3>series of partial sums</h3>

The partial sums, taken 3 terms at a time, are

  1+2-3 = 0

  4+5-6 = 3

  7+8-9 = 6

...

  97+98-99 = 96

So the original series is equivalent to ...

  0 +3 +6 +... +96 = 3×1 +3×2 +... +3×32 = 3×(1 +2 +... +32)

That is, the sum is 3 times the sum of the consecutive integers 1..32.

__

<h3>consecutive integers</h3>

The sum of integers 1..n is given by the equation ...

  s(n) = n(n+1)/2

__

<h3>series sum</h3>

Using this to find the sum of our series, we find it to be ...

  series sum = 3 × (32)(33)/2 = 1584

_____

<em>Alternate solution</em>

The given series is the sum of integers 1-99, with 6 times the sum of integers 1-33 subtracted. That is, ...

  1 + 2 - 3 + 4 + 5 - 6 = 1+2+3+4+5+6 -2(3 +6) = 1+2+3+4+5+6 -6(1+2)

Continuing on to ...97 +98 -99 gives the result s(99) -6s(33).

Computed that way, we find the sum to be ...

  (99)(100)/2 -6(33)(34)/2 = 4950 -3366 = 1584

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D none of the above
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