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Dmitry [639]
3 years ago
12

In which scenarios are surveys appropriate? or when is it appropriate to use experiments?

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

1. Surveys are used to obtain specific information from a group of people. It is administered by politicians, professionals, sociologists, and other groups to obtain data from their subjects of interest.

2. Experiments are used to establish cause-and-effect relationships. Scientists use them for highly-controlled tests to give/withdraw credence to some hypotheses.

Step-by-step explanation:

Surveys, when applied to human subjects, are used to obtain data from a selected sample of subjects. Surveys, which can be applied through mails, telephones, the internet, in-person, and through other means are aimed at getting the opinions, thoughts, and beliefs of the participants. It is administered by politicians, professionals, sociologists, and other groups to obtain data from their subjects of interest. This data can be qualitative or quantitative.

Experiments are administered to provide support or refute a given hypothesis. They establish cause and effect relationships. Scientists use them for highly-controlled tests to give/deny credence to some hypotheses. Positive controls establish the hypothesis as true. They could be conducted in the laboratory, in the field, or through observations.

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3 years ago
Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

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\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
3 years ago
PLS HELP
Ganezh [65]

Answer:

Hello! symmetry

Step-by-step explanation:

Symmetry is a mirror image of an image.

Cut a hexagon in half for example

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Helga [31]

Answer:

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