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Lelechka [254]
4 years ago
12

Multiply (2y²-1) by (2y³+5y²) please dasdo ​

Mathematics
1 answer:
algol134 years ago
5 0

Answer:

4y^{5} + 10y^{4} - 2y³ - 5y²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

2y²(2y³ + 5y²) - 1(2y³ + 5y²) ← distribute both parenthesis

= 4y^{5} + 10y^{4} - 2y³ - 5y²

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