The limit of the function tan 6x/sin 2x as x approaches zero is determined by first substituting x by zero. This is equal to zero over zero which is indeterminate. Using L'hopital's rule, we derive each term in the numerator and denominator separately. This is equal to 6 sec^2 x / 2 cos 2x. when substituted with zero again, the limit is 1/2.
The greatest common factor is 4r so
4r(d-4)
3h - 2(1 + 4h)
Multiply the bracket by -2:
3h -2 - 8h
Then, subtract the variables.
3h - 8h - 2
-5h - 2
∴The answer is -5h - 2
Answer:
4x - 2
Step-by-step explanation:
(2(3x-2))+(-2(x-1))
2(3x-2)-2(x-1)
2(3x-2-(x-1))
2(3x-2-<u>x</u><u>+</u><u>1</u><u>)</u>
<u>2</u><u>(</u><u>2x-1</u><u>)</u>
<u>4x-2</u>
Answer/Step-by-step explanation:
Given :
The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x):
To Find: two types of transformations that can be used to transform f(x) to g(x).
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Part A: Describe two types of transformations that can be used to transform f(x) to g(x). (2 points)
Solution Part A:
f(x) = x/5 + y/(-10) = 1
=> 2x - y = 10
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Part B: Solve for k in each type of transformation. (4 points)
Solution Part B:
g(x) = x/(-3) + y/6 = 1
=> 2x - y = - 6
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an equation for each type of transformation that can be used to transform f(x) to g(x). (4 points)
Solution Part C:
Transformations :
g(x) = f(x) + 16
g(x) = f(x + 8)
