Answer:
The p-value would be 0.0939
Step-by-step explanation:
We can set a standard t-test for the Null Hypothesis that ![H_0: 18.2\geq 17](https://tex.z-dn.net/?f=H_0%3A%2018.2%5Cgeq%2017)
The test statistic then takes the form
![t=\frac{18.2-17}{3.9/\sqrt{15}}=1.317](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B18.2-17%7D%7B3.9%2F%5Csqrt%7B15%7D%7D%3D1.317)
with this value we then can calculate the probability that is left to the right of this value
. From theory we know that t follows a standard normal distribution. Then
which is smaller than the p-value set by Breyers of 0.10
Critical value z_{0.05}=-1.645
Decision Rule, Reject H if z< -1.645
We do not reject the null hypothesis.
<h3>What is the
Decision?</h3>
Generally, the equation for the hypothesis is mathematically given as
H P=0.3
H2:P<0.13
Therefore
![z=\frac{p'-p}{\sqrt{\frac{p(1-p)}{n}}}\\\\\\z=\frac{0.11-0.13 }{\sqrt{\frac{0.13(1-0.13)}{76}}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bp%27-p%7D%7B%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%5C%5C%5C%5C%5C%5Cz%3D%5Cfrac%7B0.11-0.13%20%7D%7B%5Csqrt%7B%5Cfrac%7B0.13%281-0.13%29%7D%7B76%7D%7D%7D)
z=-0.52
In conclusion, from the table
Critical value z_{0.05}=-1.645
Decision Rule, Reject H if z< -1.645
In conclusion, we do not reject the null hypothesis.
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Prrime factors of 2015 are the number that mltiply to get it exg
prime factors of 100 are 2,2,5,5 becase if you multiply them together you get 100
so prime factors of 2015=5,13,31
then the sum is add ing them togherther
5+13+31=49
a
answer is 49