Ask question

Ask question

All categories

3 years ago

10

How many people averaged 4,000 or more steps each day? (25 POINTS FOR BRAINLIEST) How many people averaged 4,000 or more steps e

ach day? A): 10 B): 12 C): 19 D): 22

1 answer:

Andrews [41]3 years ago

4 0

Answer:

The answer is D: 12

You might be interested in

2. A skydiver jumps from a plane from an altitude of 6000 ft. An observer on the ground measures the skydiver’s altitude at time

Igoryamba

I believe the y intercept is 4500 ft, since t=0, and the slope of the line would be 1500/( distance from t=0 to the x coordinate for 6000), the person is probably acending since it went from 4500 to 6000. Idk C D cause I don't have the graph

3 0

4 years ago

Find the distance between the following two points: (-1,6) and (-8,9). Round to the nearest TENTH.

laila [671]

Answer:

-9, 15

Step-by-step explanation:

Add them both together to get your answer.

8 0

3 years ago

Pls ASAP help it’s math

Lena [83]

Who is ASAP and why do I need to help them lol

4 0

3 years ago

element X is a radioactive isotope such that every 21 years, its mass decreases by half. Given that the initial mass of a sample

pashok25 [27]

Answer:

The percentage rate of decay per year is of 3.25%.

The function showing the mass of the sample remaining after t is $A(t) = 80(0.9675)^t$

Step-by-step explanation:

Equation for decay of substance:

The equation that models the amount of a decaying substance after t years is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Every 21 years, its mass decreases by half.

This means that $A(21) = 0.5A(0)$ . We use this to find r, the percentage rate of decay per year.

$A(t) = A(0)(1-r)^t$

$0.5A(0) = A(0)(1-r)^{21}$

$(1-r)^{21} = 0.5$

$\sqrt[21]{(1-r)^{21}} = \sqrt[21]{0.5}$

$1 - r = 0.5^{\frac{1}{21}}$

$1 - r = 0.9675$

$r = 1 - 0.9675 = 0.0325$

The percentage rate of decay per year is of 3.25%.

Given that the initial mass of a sample of Element X is 80 grams.

This means that $A(0) = 80$

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 80(1-0.0325)^t$

$A(t) = 80(0.9675)^t$

The function showing the mass of the sample remaining after t is $A(t) = 80(0.9675)^t$

8 0

3 years ago

Read 2 more answers

Help pleassee and thank you .

vampirchik [111]

Answer:

please and thank you are the magic words

6 0

4 years ago