Question

(05.06)A chocolate bar measures 40 mm wide, 80 mm long, and 5 and 1 over 2 mm high. Will’s Wrapping Company is making a wrapper to cover the chocolate bar. Use the correct net and determine how much paper will be needed to make the wrapper.
The net of a rectangular prism with a height of 40 millimeters, a length of 80 millimeters, and a width of 5 and 1 over 2 millimeters.

Will’s Wrapping Company needs 3,860 mm2 of paper to wrap the chocolate bar.
Will’s Wrapping Company needs 7,720 mm2 of paper to wrap the chocolate bar.
Will’s Wrapping Company needs 8,160 mm2 of paper to wrap the chocolate bar.
Will’s Wrapping Company needs 15,440 mm2 of paper to wrap the chocolate bar.

Answer 1

Answer:

Will’s Wrapping Company needs 7,720 mm2 of paper to wrap the chocolate bar.

Step-by-step explanation:

we know that

The amount of paper needed to make the wrapper is equal to the surface area of the chocolate bar

The surface area of a rectangular prism (chocolate bar) is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of he prism

In this problem we have

$L=80\ mm\\W=5\frac{1}{2}\ mm=5.5\ mm\\H=40\ mm$

Find the area of the base

$B=LW=(80)(5.5)=440\ mm^2$

Find the perimeter of the base

$P=2(L+W)=2(80+5.5)=171\ mm$

Find the surface area

$SA=2(440)+171(40)\\SA=7,720\ mm^2$