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2 years ago

What is cm3 measurement?

Mathematics

1 answer:

Darina [25.2K]2 years ago

8 0

Cm³ measurement is the volume measurement in calculations

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If Jamie's paddling pool has a diameter of 10m, what is its area in square meters?<br> pls help

Over [174]

Answer:

use app Gauthmath its will give you the answer

6 0

2 years ago

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A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t

Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = $\binom{n}{k}p^{K}q^{n-k}$

In this formula n = number of trials

k = number of success

(n-k) = number of failures

p = probability of success in one trial

q = (1-p) = probability of failure in one trial

In this sum n = 5

k = 2

number failures (n-k) = (5-2) = 3

p = 2% which can be written as .02

q = 98% Which can be written as .98

Now putting these values in the formula

P = $\binom{5}{2}(.02)^{2}(.98)^{5-2}$

P = $\binom{5}{2}(.02)^{2}(.98)^{3}$

$\binom{5}{2}= 5!/3!2!$

= 5×4×3×2×1/3×2×1×2×1

= 5×2 =10

P = 10×(.02)²×(.98)³

= .0037 or .37%

4 0

3 years ago

Read 2 more answers

Help please algebra

Murljashka [212]

The answer is D. -24 - 49i/13

4 0

2 years ago

What is the value of the expression 9+4n-1 when n = 3?

Nookie1986 [14]

First you multiply 4*n and n=3 so 4*3 = 12
then you have 9+12-1
9+12= 21
21-1=20

so your answer would be 20

3 0

3 years ago

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Among 420 randomly selected employees at a company, the mean number of hours of overtime worked per month is 10 hours and the st

kari74 [83]

The margin of error of the random selection is 0.20

The given parameters are:

$n = 420$ --- the sample size

$\sigma = 1.6$ --- the standard deviation

$\bar x = 10$ --- the mean

$\alpha = 99\%$ --- the confidence level.

The margin of error (E) is calculated as follows:

$E = z \times \sqrt{\frac{\sigma^2}{n}}$

So, we have:

$E = z \times \sqrt{\frac{1.6^2}{420}}$

$E = z \times \sqrt{\frac{2.56}{420}}$

The z-value for 99% confidence level is 2.576.

Substitute 2.576 for z

$E = 2.576 \times \sqrt{\frac{2.56}{420}}$

$E = 2.576 \times \sqrt{0.006095}$

Take square roots

$E = 2.576 \times 0.0781$

Multiply

$E = 0.2012$

Approximate

$E = 0.20$

Hence, the margin of error is 0.20