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solong [7]
3 years ago
15

What is cm3 measurement?

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0
Cm³ measurement is the volume measurement in calculations
You might be interested in
Find the common difference of the following sequence.​
Darya [45]

You have the correct answer. It is choice B) -1/4

=======================================================

Explanation:

This is because we're adding -1/4 to each term to get the next one. In other words, we're subtracting 1/4 from each term to get the next one.

  • term2 = term1+(d) = 1/2 + (-1/4) = 1/2 - 1/4 = 2/4 - 1/4 = 1/4
  • term3 = term2+(d) = 1/4 + (-1/4) = 1/4 - 1/4 = 0
  • term4 = term3+(d) = 0 + (-1/4) = 0 - 1/4 = -1/4
  • term5 = term4+(d) = -1/4 + (-1/4) = -2/4 = -1/2

and so on.

----------

To find the common difference, all we have to do is subtract any term from its previous one.

For example:

d = (term2) - (term1)

d = (1/4) - (1/2)

d = (1/4) - (2/4)

d = (1-2)/4

d = -1/4

The order of subtraction matters, so we cannot say d = term1-term2.

3 0
3 years ago
The​ ____ is another term for the arithmetic average.
antiseptic1488 [7]

The answer is the mean.

"For a data set, the arithmetic mean, also called the mathematical expectation or average, is the central value of a discrete set of numbers: specifically, the sum of the values divided by the number of values."- Wikipedia

3 0
3 years ago
Help ASAP......
maria [59]

Heya User !

Your Answer is in the attachment, do check out.

MᎥssAbhᎥ ☁

3 0
2 years ago
ASAP! WILL MARK BRAINLIEST FOR FIRST ACCURATE ANSWER!!
snow_lady [41]

Step-by-step explanation:

3x - 2y = 12

Substituting y = 9, we find:

3x - 2 \times 9 = 12 \\  \therefore \: 3x - 18 = 12 \\ \therefore \: 3x  = 12 + 18  \\ \therefore \: 3x  = 30 \\ \therefore \: x  =  \frac{30}{3} \\ \therefore \: x  = 10 \\  \therefore \: A (...., 9) = A (10, \: 9)

Similarly, solving for point B (4, __) =B (4, 0)

7 0
3 years ago
Does anyone know the answer to both these questions ???
gavmur [86]

answer for 9 is 6cm not sure about 10

5 0
3 years ago
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