4x + 4y
8a + 24b
6x + 33y
63a + 54b
3ca + cb
2yx + 11yx
Answer:
The largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb
Step-by-step explanation:
Given
μ = Mean = 10.4 lb
σ = Standard deviation = 3 lb
Using a confidence level of 90%,
We'll need to first determine the z value that correspond with bottom 5% of consumption of banana
α = 5%
α = 0.05
So,
zα = z(0.05)
z(0.05) = -1.645 ----- From z table
Let x represent the largest annual per capita consumption of bananas
The relationship between x and z is
x = μ + zσ
By substitution;
x = 10.4 + (-1.645) * 3
x = 10.4 - 4.935
x = 5.465
Hence, the largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb
The mean of the sample given by 44,22,11,17,21 will be given by:
the sum of x's will be:
44+22+11+17+21
=115
n=5
therefore the mean will be:
μ=115/5
=23
Answer:
x= log120/7log3
Step-by-step explanation:
7x=log3 120
7x= log120/log3/7
x= log120/7log3
