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DerKrebs [107]
3 years ago
10

Gas costs $2.05 per gallon. You go on a trip of 150 miles and your car gets 25 miles per gallon. How much will you spend on gas?

Mathematics
1 answer:
Inessa05 [86]3 years ago
4 0

Answer: 12.30 dollars will be spent

Step-by-step explanation: If you go on a trip of 150 miles and each mile is 25 miles per gallon, I divided 150 miles from 25 = 6. Then each gallon cost $2.05 dollars, if we want to know how much will they spend on gas you have to multiply how much per mile and how much it cost. So 2.05 times 6 = 12.30.

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Find equation where line passes through (7,8) and perpendicular to line y=8
forsale [732]
Since in y=8, the slope is 0 (because there is no x) and b is 8 in y=mx+b, we know that the perpendicular line is x=(something) because the perpendicular lines of y=<number> are x=<number> due to that y=<number> equations are strictly horizontal while x=<number> equations are strictly vertical. Since we know that x=<number> has to pass through (7, 8), x =7
5 0
3 years ago
A number increased by 10 is 114
Tanzania [10]

So X + 10 = 114
Isolate x by subtracting 10 from both sides
X = 104
Your number that is increased by 10 to get 114 is 104
4 0
3 years ago
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Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
[SCREENSHOT INCLUDED] Which of the following is the best estimate of f '(2) based on this table of values?
mel-nik [20]

Using derivatives, it is found that the best estimate of f '(2) based on this table of values is of 10.

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From <u>x = 2 to x = 4</u>, it is given by:

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The average of these rates is:

A = \frac{r_1 + r_2}{2} = \frac{9 + 11}{2} = 10

Hence, the best estimate of f '(2) based on this table of values is of 10.

To learn more about derivatives, brainly.com/question/18590720

6 0
2 years ago
Keri has a spinner with sections labeled Black,
Schach [20]

Answer:

50%

Step by step explanation

100 divided by 4 is 25

Since it is both blue and black, it is doubled from 25 to 50

4 0
3 years ago
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