1) Find the distance between -49.75 and 31.5 on a number line.
1 answer:
Answer:
<u>81.25</u>
Step-by-step explanation:
Because you want to know the total distance, calculate how many digits -49.75 is away from 0. <u>It is 49.75 digits away from 0.</u>
Now calculate how many digits 31.5 is away from 0.<u> It is 31.5 digits away from 0.</u>
Finally, add those two distances together so that you know the total distance:
49.75+31.5 = 81.25
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| \
| \
| 16 \
| \
|______\
12
Envision this as a right triangle, with one leg of 12 miles, and the other 16 miles. Solve using the Pythagorean Theorem a²+b²=c²:
12²+16²=c²
400 = c²
20=c...they live at least 20 miles from each other.
Answer:
O V=3(10XB)(12)
Step-by-step explanation:
recall again, sin²(θ) + cos²(θ) = 1.