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aliina [53]
3 years ago
12

89% of 195 Can you help me?

Mathematics
2 answers:
Degger [83]3 years ago
4 0
The answer would be 173.55.

Explanation: it just is
DochEvi [55]3 years ago
4 0

Answer:

173.55

Step-by-step explanation:

89/100 × 195

0.89×195

173.55

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18 cm 18 cm 9 cm Area:​
Alik [6]

Answer:

2916 cm

Step-by-step explanation:

In area you have to multiply

So all I did was

18x18x9

which equals 2916

7 0
2 years ago
ASAAPPPPPP!!!!! Complete the tables of values
velikii [3]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

a^{-m} ⇔ \frac{1}{a^{m} } and a^{0} = 1

Substitute the values of x into 4^{-x}

x = 0 → 4^{0} = 1 ⇒ a = 1

x = 2 → 4^{-2} = \frac{1}{4^{2} } = \frac{1}{16}, hence

b = \frac{1}{16}

x = 4 → 4^{-4} = \frac{1}{4^{4} } = \frac{1}{256}, hence

c = \frac{1}{256}

6 0
3 years ago
Enter the y coordinate of the solution to this system of equations.
riadik2000 [5.3K]
-x-y=1
-y=1+x
y=-1-x

-1-x=-2x+9
-x=-2x+10
x=10

y=-1-10
y=-11
3 0
3 years ago
57,600 at 4% compounded semiannually for 3 years
patriot [66]
The answer is 64,866.96, hop this helped!!
4 0
2 years ago
X2<br>2<br>ab<br>ab to<br>b<br>The diagian<br>K<br>n shows<br>rectangle. The shade<br>Find x.<br>​
Norma-Jean [14]

Answer:

x = 28 cm

Step-by-step explanation:

Given:

Area of link shaded regions = 84 cm²

Required:

The value of x (diameter of the semicircle/length of the rectangle)

Solution:

Diameter of the semicircle = 2r = x

Length of rectangle (L) = 2r = x

Radius of semicircle (r) = ½x

Width of rectangle (W) = radius of semicircle = ½x

Use 3.14 as π

Area of the link shaded regions = area of rectangle - area of semicircle

Thus:

Area of the link shaded regions = (L*W) - (½*πr²)

Plug in the values

84 = (x*½x) - (½*3.14*(½x)²)

84 = x²/2 - (1.57*x²/4)

84 = x²(½ - 1.57/4)

84 = x²(0.5 - 0.3925)

84 = x²(0.1075)

Divide both sides by 0.1075

84/0.1075 = x²

781.4 = x²

√781.4 = x

27.9535329 = x

x = 28 cm

5 0
3 years ago
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