Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
![x=18.25](https://tex.z-dn.net/?f=x%3D18.25)
![y=13.25](https://tex.z-dn.net/?f=y%3D13.25)
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
If you want it to be a slope intercept form, the first you have to find slope.
y2-y1/x2-x1
2-0/6-0
2/6 = 1/3
Then you need to find the y intercept. Plug in the x and y value in y=mx+b.
2=1/3(6)+b
2=2+b
0=b
ANSWER: y=1/3x+0
Hope this helps and is correct :)
Answer:
800 ft
Step-by-step explanation:
2/3 minutes = 2/3 min * 60 sec/min = 40 sec
5 ft/sec * 40 sec = 800 ft
Answer:
Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .
Step-by-step explanation:
We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;
Mean,
= 1.3 cm and Standard deviation,
= 0.01 cm
Also, since distribution is normal;
Z =
~ N(0,1)
Let X = range of diameters
So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)
P(X < 1.33) = P(
<
) = P(Z < 3) = 0.99865
P(X <= 1.27) = P(
<
) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865
= 0.00135
P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .
Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .
Answer:
10.3cm=0.103
Step-by-step explanation:
Hope this helped :)
-<em>El</em>