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4 years ago

Determine the direction that this parabola opens y=-5x^2-10x-15

1 answer:

8 0

The parabola opens down.

If the a value is positive it opens up. If it's negative it opens down. If it is 0, it's not quadratic. The a value here is -5

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What do you say when you see an empty parrot cage?

irina1246 [14]

Oh no my parrot is missing

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3 years ago

How many 4 digit numbers are there with the sum of the four digits equal to 34

Masteriza [31]

Answer:

Step-by-step explanation:

THE LARGEST 4 DIGIT NUMBER IS 9999 WHICH HAS SUM OF DIGITS 9+9+9+9 =36 SO TO HAVE A SUM OF DIGITS 34 ,WE HAVE TO TAKE 2 AWAY THERE ARE TWO WAYS TO DO THAT IS

1) TAKE 2 AWAY FROM 1 OF THE 9"S AND THE SET OF THE DIGITS (7,9,9,9)

2)TAKE 1 AWAY FROM 2 OF THE 9"S AND THE SET OF DIGITS (8,8,9,9)

THERE ARE 4 ARRANGEMENTS OF THE DIGITS (7,9,9,9) BECAUSE THERE ARE FOUR POSITIONS FOR THE DIGITS THOUSANDS,HUNDREDES,TENS AND UNITS SO WE CAN PICK A P[OSITION FOR THE 7 IN (4,1) = FOUR WAYS ( THERE ARE 7,9,9,9, 9,7,9,9, 9,9,7,9, 9,9,9,7

THERE ARE SIX ARRANGEMENTS OF THE DIGITS (8,8,9,9, BECAUSE THERE ARE FOUR POSITIONF FOR THE DIGITS THOUSANDS , HUNDRED , TENS AND UNITS SO WE CAN PICK A POSITIONS FOR THE 28"S IN (4,2) = 6 WAYS THEY ARE 8,8,9,9, 8,9,8,9, 8,9,9,8, SO THAT 4+6 OR 10 WAYS

3 0

4 years ago

Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec

german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

Let's start with sin here. $\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}$ Therefore, because sin is y/r, r = $\sqrt{5}$ and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = $\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}$

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = $4\sqrt{2}$ . Now, to find csc, we have to do r/y.

csc = $\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}$

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = $\sqrt{7/16}$ = $\frac{\sqrt{7}}{4}$

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = - $\sqrt{7/9} = \frac{-\sqrt{7}}{3}$

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = $(\frac{-\sqrt{6}}{2})^{2}$

1 + cot^2 = 6/4

cot^2 = 2/4

cot = $\frac{\sqrt{2}}{2}$

tan = $\sqrt{2}$

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

$(\frac{2}{\sqrt{2}})^2$ + 1 = sec^2