Please help me it’s for homwork

Write the following expression in exponential form: 7.2 × 7.2 × 7.2 × 7.2 × 7.2 × 7.2 7.2 × 6 67.2 7.26 7.2 + 6

9966 [12]

The exponential form of the expression will be 7.2^6

4 0

4 years ago

if there are four trucks parked in line and after the first truck each truck weighed 2 more tons than the one before. They all w

algol13

Each truck weighs five tons.

1st truck: n
2nd truck: n + 2
3rd truck: n + 4
4th truck: n + 6

n + n + 2 + n + 4 + n + 6 = 32
4n + 12 = 32
- 12 - 12
--------------------
4n = 20
---- ------
4 4

n = 5

6 0

4 years ago

Write an equation for the function that passes through the points (1,3/2) and (3/2,2)

kirill [66]

Answer:

y = 1x + 1/2

Step-by-step explanation:

y2 - y1 / x2 - x1

2 - 3/2 / 3/2 - 1

= 1/2 / 1/2

= 1

y = 1x + b

3/2 = 1(1) + b

3/2 = 1 + b

1/2 = b

6 0

3 years ago

If y varies inversely as x and y is 2.5 when x is 6, what is y when x is 4?

Lady_Fox [76]

Yvaries as x means
y=kx where k is constant
y=2.5
x=6
find k
2.5=k6
divide bot sides by 6
2.5/6=k (leave as that an simplfy later)

if x=4, what is y
y=(2.5/6)*4
y=10/6
y=5/3
y=1 and 2/3

5 0

3 years ago

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes