Can anyone tutor me on linear equations?

1 answer:

5 0

Linear equations----an equation between two variables that gives a straight line when plotted on a graph.

if u need help u can pm me or post it on my profile

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Find the value(s) of x where the tangent to the graph of y=e^5x is parallel to the

Alik [6]

Answer:

There are none.

Step-by-step explanation:

No calculus involved:

The line, in slope-intercept form, has equation $y=-10x+17$ , ie is always decreasing (easy to spot applying the definition)

Meanwhile, $y=e^{5x}$ is always increasing over its domain.

At no point the tangent will be decreasing.

Let's use calculus

We are to solve the equation $y'(x) = -10 \rightarrow 5e^{5x} = -10 \rightarrow e^{5x}=-2$ which has no real solutions.

8 0

3 years ago

What is the sum of the interior angles in this shape?

Dmitrij [34]

Answer:

720° :)

Step-by-step explanation:

You can find the total interior angle for any shape using the following (n being the number of sides):

S = ( n - 2 ) × 180 °

S = (6-2) * 180

S = 720

5 0

3 years ago

Read 2 more answers

Let f and g be the functions defined by f(x) = 10^ (x+2 / 3) and g(x) = log (x3 / 100) for all positive real numbers,

Vaselesa [24]

Answer:

F(x) and g(x) are not inverse functions.

Step-by-step explanation:

In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.

As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.

$[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x$ [/tex]