All categories

3 years ago

43 divided by 569= ?

Mathematics

2 answers:

katen-ka-za [31]3 years ago

7 0

The answer to your question is 13.2325581395<span> or round it off to 13</span>

krok68 [10]3 years ago

4 0

43 divided by 569 is 24,467

You might be interested in

Simplify -4 1/6 - -6 1/3 Which of the following is correct?

leonid [27]

Answer:

its 2 1/6 (B)

Step-by-step explanation:

3 0

3 years ago

The original price of a video game is $32.99 before tax. When Mario bought the video game it rang up as $26.39 before tax. He th

mihalych1998 [28]

Answer:

Part A: The percent discount on game is 20%.

Part B: Mario paid a total of $28.50 including sales tax.

Step-by-step explanation:

Given that:

Part A:

Original price of video game = $32.99

Discounted price = $26.39

Amount of discount = 32.99 - 26.39 = $6.60

Discount percent = $\frac{Amount\ of\ discount}{Original\ price}*100$

Discount percent = $\frac{6.60}{32.99}*100 = 0.20*100$

Discount percent = 20%

Part B:

Sales tax = 8% of discounted price

Amount of sales tax = $\frac{8}{100}*26.39 = 0.08*26.39$

Amount of sales tax = $2.11

Total amount = $26.39 + $ 2.11 = $28.50

Hence,

Part A: The percent discount on game is 20%.

Part B: Mario paid a total of $28.50 including sales tax.

5 0

2 years ago

Brainliest to correct quick

musickatia [10]

Answer is <

Why? 1/4 is smaller than 1/2

1/4 can be 4 slices while 1/2 can be 2 slices

2 slices > 4 slices

3 0

2 years ago

Read 2 more answers

What is 3/4 of 16/21? worked out please

timofeeve [1]

Of means multiplication

So

$\frac{3}{4} \sf{of} \frac{16}{21} = \frac{3}{4} \times \frac{16}{21}$

And then simplify the numerator ad denominator

= $\frac{3 \times 16}{4 \times 21} = \frac{\ 1 \times 16}{4 \times 7}$

And simplify the numerator and denominator again

= $\frac{\ 1 \times 16}{4 \times 7} = \frac{\ 1 \times 4}{1 \times 7}$

And we are finally left with the answer which is $\frac{4}{7}$

5 0

3 years ago

F(x)=2x^2-3x+7 evaluate f(-2)

Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let p(x)=kpx+dp and q(x)=kqx+dq than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)

So you want:

−2kpk2q=0

and

kpkq=−1

and

2kpd2p−3kpdq+7=0

Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .

Answer: there are no such linear functions.

6 0

2 years ago