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maw [93]
2 years ago
10

Pls pls pls helppp ------------------

Mathematics
2 answers:
aliina [53]2 years ago
7 0

Answer:

\fbox {x-intercepts : (1, 0) and (-3, 0)}

\fbox {Roots : x = 1, x = -3}

Step-by-step explanation:

<u>Given</u> :

  • y = 4x² + 8x - 12

4 cancels throughout.

  • <u>y = x² + 2x - 4</u>

<u>Solving by quadratic formula</u> :

  • x =  -8 ± √(8)² - 4(4)(-12) / 8
  • x = -8 ± √64 + 192 / 8
  • x = -8 ± √256 / 8
  • x = -8 ± 16 / 8
  • x = -1 ± 2
  • x = 1 and x = -3

∴ Hence, the x-intercepts are (1, 0) and (-3, 0). The roots of the equation are 1 and -3.

horrorfan [7]2 years ago
7 0

Answer:

y = 4x^2 + 8x - 12

4(x^2 + 2x - 3) = 0

4(x - 1)(x + 3) = 0

x = 1, -3

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Answer:

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The general solution values  

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Step-by-step explanation:

Explanation:-

Given equation is  

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<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

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x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

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