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2 years ago

9

What is the sum of square root of -2 and square root of -18

1 answer:

Tasya [4]2 years ago

7 0

Answer is B
4 square root of 2i

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Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5

MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

$\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7$

5 0

2 years ago

31. Solve for x.<br> (4x + 70°<br> (x + 5)

Lady_Fox [76]

Answer:cq cat cat cat cat

Step-by-step explanation:

8 0

2 years ago

2x-3y> or equal to 12

Drupady [299]

Answer:

it's not greater than it would be 2x-3y because you can add then together because the not the same variable

Step-by-step explanation:

5 0

3 years ago

Find the indefinite integrals, if possible, using the formulas and techniques you have studied so far in the text.(a) 11 x4 dxTh

hoa [83]

Answer:

a) This integral can be evaluated using the basic integration rules. $\int 11x^{4}dx = \frac{11}{5} x^{5}+C$

b) This integral can be evaluated using the basic integration rules. $\int 8x^{1}x^{4}dx=\frac{4}{3}x^{6}+C$

c) This integral can be evaluated using the basic integration rules. $\int 3x^{31}x^{4}dx=\frac{x^{36}}{12}+C$

Step-by-step explanation:

a) $\int 11x^{4}dx$

In order to solve this problem, we can directly make use of the power rule of integration, which looks like this:

$\int kx^{n}=k\frac{x^{n+1}}{n+1}+C$

so in this case we would get:

$\int 11x^{4}dx=11 \frac{x^{4+1}}{4+1}+C$

$\int 11x^{4}dx=11 \frac{x^{5}}{5}+C$

b) $\int 8x^{1}x^{4}dx$

In order to solve this problem we just need to use some algebra to simplify it. By using power rules, we get that:

$\int 8x^{1}x^{4}dx=\int 8x^{1+4}dx=\int 8x^{5}dx$

So we can now use the power rule of integration:

$\int 8x^{5}dx=\frac{8}{5+1}x^{5+1}+C$

$\int 8x^{5}dx=\frac{8}{6}x^{6}+C$

$\int 8x^{5}dx=\frac{4}{3}x^{6}+C$

c) The same applies to this problem:

$\int 3x^{31}x^{4}dx=\int 3x^{31+4}dx=\int 3x^{35}dx$

and now we can use the power rule of integration:

$\int 3x^{35}dx=\frac{3x^{35+1}}{35+1}+C$

$\int 3x^{35}dx=\frac{3x^{36}}{36}+C$

$\int 3x^{35}dx=\frac{x^{36}}{12}+C$

6 0

2 years ago

Can y’all please help if you know this I’m kinda lost !

Zepler [3.9K]

Answer:

Part A) x = 5

Part B) B = 113 degrees, C = 95 degrees. E = 95 degrees

Step-by-step explanation:

<u>Part A:</u>

We know that the sum of all angles in a pentagon are 540 degrees.

We already have two angles: 113 and 124 which add up to 237.

Make an equation out of all the information.

237 + 98 + 3x + 19x - x = 540

3x + 19x - x = 105

21x = 105

x = 5

<u>Part B:</u>

Substitute 5 for each x

measure B: 98 + 3x = 98 + 3*5 = 98 + 15 = 113

measure C: 100 - x = 100 - 5 = 95

measure E: 19x = 19* 5 = 95

<u></u>

8 0

2 years ago