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Alja [10]
3 years ago
7

There are 16 children and 24 adults what percent are children and what percent are adults

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0

Answer:

40% is children and 60% in adults

Step-by-step explanation:

so if you add the two you have 40, 100% of 40 is 40 and 50% is 20, so we know that the children percent is less than 50, if you go through you will find that 40% of 40 is 16 therefor leaving the rest (aka 60%) to be adults

Nuetrik [128]3 years ago
6 0

Answer:

60% adult

40% children

Reasoning:

Add the adults and children first.

Then find the ratios of the children and parent percentages.

16:40 children

24:40 adult

16/40=2/5=0.4=40% children

24/40=3/5=0.6=60% adult

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Answer:

2pi

Step-by-step explanation:

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4 years ago
The ratio of blue marbles to white marbles Simran's bag is equal to 1 to 2. If there are 20 blue marbles how many white marbles
Nastasia [14]
There are 40 white marbles.
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A line is parallel to y = 2x - 8 and
Angelina_Jolie [31]

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the line is y=2x+7

Step-by-step explanation:

6 0
3 years ago
Given 2 and 1 over 10 times negative seven times 5 over 12, determine the product.
yKpoI14uk [10]

The solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8

<h3>How to Multiply Fractions?</h3>

2 and 1 over 10 times negative seven times 5 over 12 can also be expressed as; 2¹/₁₀ * ⁽⁻⁷ * ⁵⁾/₁₂

Multiplying out the bracket gives;

²¹/₁₀ * -³⁵/₁₂

Dividing by common factors gives;

= ⁷/₂ *  ⁻⁷/₄

= -49/8

= -6¹/₈

This can also be written as negative six and 1 over 8

Thus, we conclude that the solution to the algebra 2 and 1 over 10 times negative seven times 5 over 12 is; negative six and 1 over 8

Read more about Multiplication of fractions at; brainly.com/question/7335118

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4 0
2 years ago
In a rectangle FGHI, diagonals FH and GI intersect at E<br> What is the length of FH?
Hunter-Best [27]

Answer:

The length of \overline {FH} is;

D. 38 units

Step-by-step explanation:

The given parameters are;

The type of the given quadrilateral FGHI = Rectangle

The diagonals of the quadrilateral = \overline {FH} and \overline {GI}

The length of IE = 3·x + 4

The length of EG = 5·x - 6

We have from segment addition postulate, \overline {GI} = IE + EG

The properties of a rectangle includes;

1) Each diagonal bisects the other diagonal into two

Therefore,  \overline {FH} bisects \overline {GI}, into two equal parts, from which we have;

IE = EG

\overline {GI} = IE + EG

3·x + 4 = 5·x - 6

4 + 6 = 5·x - 3·x = 2·x

10 = 2·x

∴ x = 10/2 = 5

From which we have;

IE = 3·x + 4 = 3 × 5 + 4 = 19 units

EG = 5·x - 6 = 5 × 5 - 6 = 19 units

\overline {GI} = IE + EG = 19 + 19 = 38 units

\overline {GI} = 38 units

2) The lengths of the two diagonals are equal. Therefore, the length of segment \overline {FH} is equal to the length of segment \overline {GI}

Mathematically, we have;

\overline {FH} = \overline {GI} = 38 units

∴ \overline {FH} = 38 units.

5 0
3 years ago
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