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djyliett [7]
3 years ago
15

Help me please!!!

Mathematics
2 answers:
marishachu [46]3 years ago
7 0

Let's say x is "number"

14) 2x-5=7

16) 6x-6=12

18) 2x+7=1

20) 8(n-3) or 8(3-n)

19) 9 + x/7=11

21) The product of 2 and the sum of 5 and t is 8

Hope this helped : )

IgorLugansk [536]3 years ago
7 0

Step-by-step explanation:

14. 2x -5 = 7

2x = 12

x = 6

16. 6x -6 = 12

6x = 18

x = 3

18. 2x + 7 = 1

2x = -6

x = -3

17. n/3 + 10= 12

n/3 = 2

n = 6

19. x/7 + 9 = 11

x/7 = 2

x = 14

21. 2 times the quantity of the sum of 5 and t is 8

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What’s x Pythagorean triples
nadezda [96]
We have to find x and x is the hypotenuse. We use this formula:

hyp²=side²+side²

So:

hyp²=side²+side²

hyp²= 12²+9²

hyp²= 225

hyp²= √225

hyp= 15

Therefore, the hypotenuse is 15 and x is 15.
HOPE THIS HELPS!
HAVE A GR8 EVENING ;-)

6 0
3 years ago
Suppose given △ABD and △CBD.
patriot [66]

Answer:

The required result is proved with the help of angle bisector theorem.

Step-by-step explanation:

Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that \frac{AD}{AB}=\frac{DC}{CB}

Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.

In ΔADB, AE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.

\frac{DE}{EB}=\frac{AD}{AB}   →  (1)

In ΔDCB, CE is the angle bisector

∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.

\frac{DE}{EB}=\frac{CD}{CB}    →  (2)

From equation (1) and (2), we get

\frac{AD}{AB}=\frac{CD}{CB}

Hence Proved.

5 0
3 years ago
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Rama09 [41]

Answer:

6

Step-by-step explanation:


8 0
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Answer:

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Step-by-step explanation:

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Rounded to 1 decimal place
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