Rebekah kicks a soccer ball off the ground and in the air, with an initial velocity of 25 feet per second. Using the formula H(t
) = −16t2 + vt + s, what is the maximum height the soccer ball reaches? 9.5 feet 9.8 feet 10.2 feet 10.7 feet
2 answers:
Answer:
A: 9.8
Step-by-step explanation:
took the test
H(t)=-16t^2+25t
The maximum height occurs at the vertex of the quadratic.
The vertex of a quadratic is always at:
(x,y)=(-b/(2a), (4ac-b^2)/(4a))
So the maximum height is:
(4ac-b^2)/(4a), and in our equation a=-16, b=25, and c=0 so
hmax=(0-25^2)/(-64)
hmax=-625/-64
hmax=9.765625
hmax≈9.8 ft (to nearest tenth of a foot)
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