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kari74 [83]
3 years ago
9

18+ (7 - 4) x 3 I’m very confused and need help:(

Mathematics
2 answers:
baherus [9]3 years ago
8 0
Here i hope this helps

Roman55 [17]3 years ago
5 0
Start with 7-4=3
Then 3x3=9
Then 18+9=27
Answer 27
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Can someone help me with this?<br> I am not understanding this and the diagram<br> Thanks
Pavel [41]

Answer:

a) m∠FGH= 28°

b) m∠HGI =  28°

c) m ∠FGI =  56°

Step-by-step explanation:

GH bisects ∠FGI. So, ∠FGH = ∠HGI

    5x - 2   = 6x -8

     5x - 6x = 2 - 8

              -x = - 6

               x = 6

a) m∠FGH = 5x - 2 = 5 * 6 - 2 = 30 - 2 = 28°

b) m∠HGI = 6x - 8  = 6 * 6 - 8  = 36 - 8 = 28°

c) m ∠FGI = m∠FGH + m∠HGI = 28° +28° = 56°

7 0
3 years ago
If f(x) = 6 what is x?
Margarita [4]

Answer:well you don't have x because x would be 1

5 0
3 years ago
21. Graph and label the triangle with the following vertices: A(-2, 4), B(5, -3) and C(-2, -3). Determine whether the triangle i
Fynjy0 [20]
The answer to ur question is a right triangle
7 0
4 years ago
Read 2 more answers
hassan thinks his goldfish got chickenpox. He lost 70% of his collection of goldfish. If he has 60 survivors , how many did he h
Diano4ka-milaya [45]
So the complete amount of fishes were 100%
70% died and 60 are left...
so 100% - 70% = 60
100% - 70% = 30%
30% = 60 fishes...
so 10% = 20 fishes
If you complete that percentage to 100
10% = 20, 100% 200
8 0
4 years ago
Please help me on this!
denis23 [38]

Answer:

The Proof is given below.

Step-by-step explanation:

Given:

P is the center of Circle

∠ONE ≅ ∠TEN

To Prove:

∠5 ≅ ∠6

Proof:

Exterior Angle Theorem:

Exterior Angle Property of a Triangle states that measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles.

STATEMENT                                                   REASON

1. So In ΔONE,

\angle 5=\angle ONE+\angle 2     1. Exterior Angle Property of a Triangle.

2. Similarly In ΔTEN,

\angle 6=\angle TEN+\angle 1      2. Exterior Angle Property of a Triangle.

3. But , ∠ONE ≅ ∠TEN                                 3. Given

4. And P is the center of circle So

PN=PE                                             4.radius of same circle

5. ΔPEN is an Isosceles triangle,

∴ ∠ 1 ≅ ∠ 2                                                     5. Isosceles triangle property

6. ∴ ∠5 ≅ ∠6                                                  6. From 3 and 5 Transitive Property.........Proved

5 0
3 years ago
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