Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
The answer too this question is 4
Answer:
( cos40° + isin40°)
Step-by-step explanation:
To divide

=
[ cos(x₁ - x₂) + isin(x₁ - x₂)
Given

=
( cos(90 - 50)° + isin(90 - 50)°
=
( cos40° + isin40° )
Circumference =

When you plug that in you should have

Solve that and you have your answer(: I would recommend rounding to the nearest hundreth