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Umnica [9.8K]
4 years ago
10

Simplify the following y^-1z^5×y^3z^2​

Mathematics
1 answer:
adell [148]4 years ago
5 0

Answer:=y^3z^7y

Step-by-step explanation:

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Step-by-step explanation:

The equation for the area of a triangle (A_{\bigtriangleup}) is:

A_{\bigtriangleup} = \frac{1}{2}\cdot b \cdot h

Where:

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h - Height, dimensionless.

The expression for each triangle are described below:

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A_{\bigtriangleup,1} = \frac{1}{2}\cdot (3\cdot x+7)\cdot (5\cdot x -1)

Second Triangle (b = 3\cdot (3\cdot x+7), h = 2\cdot (5\cdot x -1))

A_{\bigtriangleup,2} = 3\cdot (3\cdot x+7)\cdot (5\cdot x -1)

The difference between the area of the original triangle and the area of the new triangle is:

\Delta A_{\bigtriangleup} = A_{\bigtriangleup,2}-A_{\bigtriangleup,1}

\Delta A_{\bigtriangleup} = 3\cdot (3\cdot x+7)\cdot (5\cdot x-1)-\frac{1}{2} \cdot (3\cdot x+7)\cdot (5\cdot x-1)

\Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1)

The difference between the area of the original triangle and the area of the new triangle is \Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1).

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