According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
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Answer: x = a*y + 3
Step-by-step explanation:
To make x the subject of the equation, first, we open the bracket
4x - 12/a = y
Then cross multiply:
4x - 12 = a * y ( a*y means the product of the two variables)
Add 12 to both sides of the equation
4x = a*y + 12
Divide both sides by 4 to get the value of x
x = a * y + 12/4
x = a*y + 3
I hope this helps.
Step-by-step explanation:
i will go you in the bank in co2 in the man
Answer:
I would say C
Step-by-step explanation:
because I think that 15 is the slope and the 35 is the y intercept. I could be wrong but that would be my guess