Which step can be used to prove that triangle EFG is also a right triangle?

Mathematics

1 answer:

Darya [45]3 years ago

8 0

EFG is the same as angle KLM. therefore, it is the reflection of the angle KLM

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Tammy conducted a survey to find the favorite subject of the students at her school. She asked 25 students from her math class w

almond37 [142]

Tammy's sample may not be considered valid because, on the first hand, it is said that she only asked students from her " Math Class".
If she wants to have a survey to find out the favorite subject of the students at her school, she must conduct a survey involving all the students in her school, not just in her class. What she did is just subjective. She should use a tally listing the different subjects and compare the number of students per subject. This way, she can have an objective representation of the least liked subjects and the most liked subjects of the students on her school.
Illustrating her survey through statistics may be more reliable and valid because it shows frequencies in which she can calculate easily and accurately the percentage of the number of students per subject, in a more objective manner.

7 0

4 years ago

Which of the following is equal to the fraction below?

Alecsey [184]

Wish I can help , but you didn’t show any fractions nor anything I can use to answer your question . Can you mark me brainliest for effort !?

4 0

3 years ago

Which number is greater: 1/4 or 5/4 ?

tatiyna

Answer:

1/4 < 5/4

Step-by-step explanation:

Since the numbers have the same denominator, we compare the numerators

1<5

so 1/4 < 5/4

3 0

3 years ago

Read 2 more answers

Given the formula C= 1/2t(c1-c2), solve for t.

kobusy [5.1K]

Answer:

$t=\frac{2C}{c1-c2}$

Step-by-step explanation:

$C=\frac{1}{2}t(c1-c2)\\2(C)=2(\frac{1}{2}t(c1-c2))\\2C=t(c1-c2)\\\frac{2C}{c1-c2}=\frac{t(c1-c2)}{c1-c2}\\t=\frac{2C}{c1-c2}$

3 0

3 years ago

Read 2 more answers

Help please word problem...show work please

Alona [7]

A) you must plug in 50 for variable F and solve for C

C= $\frac{5}{9}$ (50-32)
C= $\frac{5}{9}$ (18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius

B) you must solve the equation for F

C= $\frac{5}{9}$ (F-32)
C/ $\frac{5}{9}$ =F-32
C/ $\frac{5}{9}$ +32=F
F= C/ $\frac{5}{9}$ +32

dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as

F= $\frac{9}{5}$ C +32

now you just plug in 50 for the variable C in the new equation

F= $\frac{9}{5}$ (50) +32
F= 90 + 32
F= 122

50 degrees celsius is equal to 122 degrees fahrenheit

hope this helped!

6 0

4 years ago