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Neko [114]
3 years ago
10

Leroy owns a business earning $49,300 in profits, these profits are appreciating at about 2.9% each year. What are leroys profit

s after nine years ?
Mathematics
1 answer:
evablogger [386]3 years ago
7 0

Answer:

$62,167.3

Step-by-step explanation:

Profit after nine years is the amount.

Amount = Principal + Interest

Given

Earning profit = Principal = $49,300

Rate = 2.9%

Time = 9 years

Interest = Principal * Rate * Time/100

Interest = $49,300*2.9*9/100

Interest = 1,286,730/100

Interest = $12,867.30

Amount = $49,300+$12,867.30

Amount = $62,167.3

Hence leroys profits after nine years is $62,167.3

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A car's wheels spins at 1000 revolutions per minute. The diameter of the wheels is 23 inches. You want to know how fast the car
ch4aika [34]

Answer:

72,220 inches per  minute

Step-by-step explanation:

A car's wheels spins at 1000 revolutions per minute. The diameter of the wheels is 23 inches.

1 revolution = 2\pi radians

\frac{theta}{tome}=\frac{1000 \ revolution}{1 \ minuite} = \frac{1000* 2\pi }{1} =\frac{2000\pi}{1 \ minute}

Speed V= \frac{r*theta}{t}

r is the radius , theta is the angle and t is the time

We know diameter = 23  , then radius = 23/2

Speed V= \frac{23}{2}*\frac{2000\pi}{1}

Value of pi = 3.14

speed = 23000* 3.14= 72220 inches/ minute


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The owner of a bakery wants to know whether customers have any preference among 5 different flavors of muffin. A sample of 200 c
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So,, there are 5 different flavors. A total of 180 people were asked. Hence, the hypothesis that there is no significant difference is that every flavor gets 180/5=36 flavors. x^2=\sum{\frac{(x_i)^2}{m_i}}-n. In this case, mi is the proportion of the hypothesis, thus 36, n=180 and xi is the number of actual observations. Substituting the known quantities, we get that x^2=9. The degree of association is given by \sqrt{X^2}/ \sqrt{N(n-1)}. This yields around 0.10, much higher than our limit.
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Implicit differentiation Please help
Anvisha [2.4K]

Answer:

y''(-1) =8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Quotient Rule: \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

  1. Implicit Differentiation [Product Rule/Basic Power Rule]:                            -y - xy' - 2y' = 0
  2. [Algebra] Isolate <em>y'</em> terms:                                                                               -xy' - 2y' = y
  3. [Algebra] Factor <em>y'</em>:                                                                                       y'(-x - 2) = y
  4. [Algebra] Isolate <em>y'</em>:                                                                                         y' = \frac{y}{-x-2}
  5. [Algebra] Rewrite:                                                                                           y' = \frac{-y}{x+2}

<u>Step 3: Find </u><em><u>y</u></em>

  1. Define equation:                    -xy - 2y = -4
  2. Factor <em>y</em>:                                 y(-x - 2) = -4
  3. Isolate <em>y</em>:                                 y = \frac{-4}{-x-2}
  4. Simplify:                                 y = \frac{4}{x+2}

<u>Step 4: Rewrite 1st Derivative</u>

  1. [Algebra] Substitute in <em>y</em>:                                                                               y' = \frac{-\frac{4}{x+2} }{x+2}
  2. [Algebra] Simplify:                                                                                         y' = \frac{-4}{(x+2)^2}

<u>Step 5: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

  1. Differentiate [Quotient Rule/Basic Power Rule]:                                          y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}
  2. [Derivative] Simplify:                                                                                      y'' = \frac{8}{(x+2)^3}

<u>Step 6: Find Slope at Given Point</u>

  1. [Algebra] Substitute in <em>x</em>:                                                                               y''(-1) = \frac{8}{(-1+2)^3}
  2. [Algebra] Evaluate:                                                                                       y''(-1) =8
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