To solve this problem you must apply the proccedure shown below:
1. You must use the formula for calculate the surface area and the volume of the tank:

2. Solve for
in the second equation and substitute it into the first one.Then, you have:

3. Now, derivate:

4. When you solve for
, you obtain:
![2x^{3}-256=0\\ x=\sqrt[3]{\frac{256}{2}} \\ x=5.03](https://tex.z-dn.net/?f=%202x%5E%7B3%7D-256%3D0%5C%5C%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B256%7D%7B2%7D%7D%20%20%5C%5C%20x%3D5.03%20)
5. Now, you must calculate
:

Therefore, the dimensions are:
The sides of the base of the tank: 
The height of the tank: 
We have the equation: -52+18x= 2=> x = (52+2) : 18 = 3
The number is 3
Domain ( Inputs ) Range (Outputs)
2, 5, 10. 6, 15 , 30
X Y
2. 6
5. 15
10. 30
The numbers are 4 and 5 because 4 comes right before 5
1 . 9.10
2. divid and you get 95