Find the initial value of the linear function. y = 4x + 3
1 answer:
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I would recommend taking a picture of the instructions because I am not sure if you need to find the equation of the line that is parallel or perpendicular, so I will do both.
1. (3 , 2); y = 3x - 2
If the line is parallel to the given equation, the slopes have to be the SAME, so the slope(m) is 3
y = mx + b
y = 3x + b
To find b you plug in the point (3, 2) into the equation
2 = 3(3) + b
2 = 9 + b
-7 = b
The equation of the line that is parallel to the given equation is:
y = 3x - 7
To find the equation of the line that is perpendicular to the given equation, the slope has to be the exact opposite of the given slope. (you flip the sign and the number of the given slope to get the perpendicular line's slope)
The given slope is 3, the perpendicular slope is
y = mx + b
To find b, you plug in the point (3 , 2) into the equation
2 = -1 + b
3 = b
The equation of the line perpendicular to the given equation is:
Answer:
Step-by-step explanation:
Set up an equation to model the situation,
Distribute, multiply each term in the parenthesis with the term outside of the parenthesis. Don't forget the laws of exponents, when one multiplies two exponents, with the same base, then one adds the two exponents. A number with no exponential term is two the first degree meaning that it is to the power of one.