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kkurt [141]
4 years ago
14

If k(x) = 5x-6, which expression is equivalent to (k+k) (4)?

Mathematics
1 answer:
goldenfox [79]4 years ago
5 0

Answer:

<em>5(4) - 6 + 5(4) - 6</em>

Step-by-step explanation:

k(x) = 5x - 6

(k+k)(x) = 5x - 6 + 5x - 6

(k+k)(4) = 5(4) - 6 + 5(4) - 6

=> Option D is correct

Hope this helps!

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Susan makes $22 per hour in a clerical position. If she works 30 hours per week, what is her gross
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Select D $660 is the answer
4 0
3 years ago
The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
3 years ago
Read 2 more answers
Rob ran 27.2 miles less than Jasmine last week. Rob ran 10 miles. How many miles did Jasmine run?
jeka94

Answer:

Jasmine ran last week 37.2 miles

Step-by-step explanation:

Let

x ----> number of miles Rob ran last week

y ----> number of miles Jasmine ran last week

we know that

x=y-27.2 ----> equation A

x=10 ----> equation B

Substitute equation B in equation A and solve for y

10=y-27.2

y=10+27.2

y=37.2 miles

4 0
3 years ago
Laura invests $2500 in one account and $1500 in an account paying 2 % higher interest. At the end of one year she had earned $11
Crank

Answer:

$2500 - 2%

$1500 - 4%

Step-by-step explanation:

Say the interest for the $2500 is x, so the interest for the $1500 is x+0.02.

As an equation, they would look like this:

2500x+1500(x+0.02)=110

Now solve

2500+1500x+30=110

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x=0.02

That means the interest for the $2500 is 0.02, or 2%, and the interest for the $1500 is 0.04, or 4%.

6 0
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Which method do you prefer to use to find sums- count by tens and ones, use compatible numbers, or use friendly numbers and adju
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Count by tens and ones.
5 0
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