Answer:
![\displaystyle 4\sqrt[7]{x^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%5Csqrt%5B7%5D%7Bx%5E3%7D)
General Formulas and Concepts:
<u>Algebra I</u>
- Exponential Rule [Root Rewrite]:
![\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Rewrite</u>
- Split:

- Rewrite [Exponential Rule - Root Rewrite]:
![\displaystyle 4\sqrt[7]{x^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%5Csqrt%5B7%5D%7Bx%5E3%7D)
yes , because run over rise wont give you a valid answer
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
The area of the composite figure can be found by summing the whole area that made up the figure. Therefore, the area of the figure is 213.5m²
<h3>Area of a composite figure</h3>
The area of the composite figure is the sum of the area of the whole figure.
Therefore, the composite figure can be divided into 2 triangles and two rectangles.
Hence,
area of triangle1 = 1 / 2 × 10 × 13 = 65 m²
area of the triangle2 = 1 / 2 × 15 × 7 = 52.5 m²
area of the rectangle1 = 8 × 3 = 24 m²
area of rectangle2 = 7 × 6 = 42 m²
area of rectangle3 = 5 × 6 = 30 m²
Therefore,
area of the composite figure = 65 + 52.5 + 24 + 42 + 30 = 213.5 meters squared
learn more on area here: brainly.com/question/27744042
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