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balu736 [363]
3 years ago
14

Why are the solutions to the proportions 40/8 = x/10 and x/40 = 10/8 the same?

Mathematics
2 answers:
Finger [1]3 years ago
8 0

Answer:

b .

tha answer is b !

romanna [79]3 years ago
4 0

Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions \frac{40}{8}=\frac{x}{10} and \frac{x}{40}=\frac{10}{8}. We are asked to find why the solutions to our given proportions are equal.

We can solve proportions by cross multiplying them.

After cross multiplying our both proportions we will get same equation that is:

40*10=8*x

400=8x

8*x=40*10

8x=400

Since we get same equation after cross multiplying both proportions, therefore, the solutions to the given proportions would be same.

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In the equation 3/4y+1/2=3 1/4, the fractional coefficient is what
AURORKA [14]

Answer:

\frac{3}{4}

Step-by-step explanation:

Given equation: \frac{3}{4}y + \frac{1}{2} = 3 \frac{1}{4}

In the given equation, \frac{3}{4} is a coefficient and y is the variable.

coefficient is a constant number or quantity multiplied to a variable in an algebric expression. Like in the above equation \frac{3}{4} is a coefficient and y is the variable. We use term variable for y as its value may vary or change. If variable does not have any coefficient in any expression then in that case, we consider 1 as coefficient, for example: x+4, here variable have 1 as coefficient.

Hence, the fractional coefficient is \frac{3}{4}.

7 0
3 years ago
HELPPP ASAP 10 POINTSS
Free_Kalibri [48]
It should be 4 because 1.5 * 4 will give you 6
3 0
3 years ago
Stephen purchased a guitar, which was originally priced at $80 but
Sonbull [250]
$24

(ignore this i don’t have enough characters )

8 0
3 years ago
Read 2 more answers
Need answer 25 and answer 27
UNO [17]

\\ \bull\tt\dashrightarrow \dfrac{-3}{8}x-20+2x>6

\\ \bull\tt\dashrightarrow \dfrac{-3}{8}x+2x=6+20=26

\\ \bull\tt\dashrightarrow \dfrac{-3+16}{8}x=26

\\ \bull\tt\dashrightarrow \dfrac{13}{8}x=26

\\ \bull\tt\dashrightarrow x=26\times \dfrac{8}{13}

\\ \bull\tt\dashrightarrow x=8(2)=16

#27

\\ \bull\tt\dashrightarrow 0.5x-4-2x\leqslant 2

\\ \bull\tt\dashrightarrow 0.5x-2x\leqslant=2+4=6

\\ \bull\tt\dashrightarrow -1.5x\leqslant 6

\\ \bull\tt\dashrightarrow x\leqslant\dfrac{6}{-1.5}

\\ \bull\tt\dashrightarrow x\leqslant 4

8 0
3 years ago
What do I have?<br> what do I need ?<br>what should I use?
Ulleksa [173]
For a:
you have your opposite side
you need your hypotenuse
you should use the s.o.h

4 0
3 years ago
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