Start at the given point. Draw a segment from that point through the center of the circle, and extend the segment until it intersects the circle. The new point of intersection of the segment and the circle is the image of the original point.
Answer:
hey hope this helps
<h3 /><h3>Comparing sides AB and DE </h3>
AB =


DE

So DE = 2 × AB
and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.
<u>scale factor</u> = AB/DE
= 2
It's been reflected across the Y-axis
<em>moved thru the translation of 3 units towards the right of positive x- axis </em>
for this let's compare the location of points B and D
For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3
so the triangle has been shifted by 3 units across the positive x axis
If you want to multiply the two functions, the answer is a.
In fact, you have

I think that the answer is c
In rectangular form, we have the coordinates 