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Leni [432]
4 years ago
8

A pillow that usually costs $18 is marked down 25%. Which expressions can be used to find the new price of the pillow? Check all

that apply.
18 – 0.25(18)
18 – 0.75(18)
0.25(18)
0.75(18)
18(0.25) + 18
Mathematics
2 answers:
kolezko [41]4 years ago
9 0

In this case we can propose a rule of three:

$ 18 ---------------> 100%

x --------------------> 25%

Where x represents the discount made to the pillow:

x = \frac {25 * 18} {100}\\x = 0.25 * 18\\x = 4.5

So we have the new price (with the discount) is:

P = 18- (0.25 * 18)\\P = 18-4.5\\P = 13.5

In addition, if 25% is discounted we have to, the price of the pillow is 75% of the original price. That is to say:

0.75 * 18 = 13.5

Answer:

Option A

P = 18- (0.25 * 18)

Option D

P=0.75*18

OLga [1]4 years ago
4 0

Answer:

A and D

Step-by-step explanation:

can i have branliest i have never gotten it before so pweaseeee

Clair
3 years ago
Branliest Person
Clair
3 years ago
Not really its wrong
Clair
3 years ago
It's A and C
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A research collected data about the favorite car color of a particular population. He asked 250 of people about their favorite v
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Answer:

a) 20 more people said their favorite vehicle color was blue compared to those who said white.

b) 55 people said their favorite vehicle color was either black or silver

Step-by-step explanation:

(a). How many more people said their favorite vehicle color was blue compared to those who said white explain?

250 people

32% said blue. 32% of 250 is 0.32*250 = 80

24% said white. 24% of 250 is 0.24*250 = 60

80 - 60 = 20

20 more people said their favorite vehicle color was blue compared to those who said white.

(B) how many people said their favorite vehicle color was either black or silver ?

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Use De Moivre's theorem to write the complex number in trigonometric form: (cos(3pi/5) + i sin (3pi/5))^3
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By De Moivre's theorem,

\left(\cos\dfrac{3\pi}5+i\sin\dfrac{3\pi}5\right)^3=\boxed{\cos\dfrac{9\pi}5+i\sin\dfrac{9\pi}5}

We can stop here ...

# # #

... but we can also express these trig ratios in terms of square roots. Let x=\dfrac\pi5 and let c=\cos x. Then recall that

\cos5x=c^5-10c^3\sin^2x+5c\sin^4x

\cos5x=c^5-10c^3(1-c^2)+5c(1-2c^2+c^4)

\cos5x=16c^5-20c^3+5c

On the left, 5x=\pi so that

16c^5-20c^3+5c+1=(c+1)(4c^2-2c-1)^2=0

Since c=\cos\dfrac\pi5\neq1, we're left with

4c^2-2c-1=0\implies c=\dfrac{1+\sqrt5}4

because we know to expect \cos x>0. Then from the Pythagorean identity, and knowing to expect \sin x>0, we get

\sin x=\sqrt{1-c^2}=\sqrt{\dfrac58-\dfrac{\sqrt5}8}

Both \cos and \sin are 2\pi-periodic, so that

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and

\sin\dfrac{9\pi}5=\sin\left(-\dfrac\pi5\right)=-\sin\dfrac\pi5

so that the answer we left in trigonometric form above is equal to

\cos\dfrac\pi5-i\sin\dfrac\pi5=\boxed{\dfrac{1+\sqrt5}4+i\sqrt{\dfrac58+\dfrac{\sqrt5}8}}

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The ratio is 10/15.

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