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lianna [129]
3 years ago
15

The positive difference between two consecutive even perfect squares is 268. Compute the larger of the two squares. (By the way,

68 is not correct. I already checked.)
Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0

Answer:

Step-by-step explanation:

Let A, B are the required numbers.

A^2 - B^2 = 268

(A+ B) (A-B) = 268

Since A, B are consecutive even numbers, the difference between the two is 2. That is (A- B) = 2.

That gives A + B = 134

Solve the system, we have A = 68, B = 66

Check back

68^2 - 66^2 = 4624 - 4356=268

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