Question

The positive difference between two consecutive even perfect squares is 268. Compute the larger of the two squares. (By the way, 68 is not correct. I already checked.)

Answer 1

Answer:

Step-by-step explanation:

Let A, B are the required numbers.

$A^2 - B^2 = 268$

$(A+ B) (A-B) = 268$

Since A, B are consecutive even numbers, the difference between the two is 2. That is (A- B) = 2.

That gives A + B = 134

Solve the system, we have A = 68, B = 66

Check back

$68^2 - 66^2 = 4624 - 4356=268$