A total of 35+21 = 56 tickets were sold. The probability of 5 men winning is the ratio
C(21, 5)/C(56, 5) = 20,349/3,819,816 ≈ 0.00533
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C(n, k) is the number of ways k items can be chosen from n items. Its value is
= n!/(k!*(n-k)!)
Answer:
a. 6(7) + 2(3)^2 = 60
b. (5(-18)/3)-2 = -32
c. (6(10))^2 - 10/5 = 3598
d. (1-3)(1+2) = -6
Step-by-step explanation:
You can't simplify this problem any further because there are no more like terms
