Answer:
Software is the correct answer.
Explanation:
Software is the collection of programs or the group of instruction through which the computer system's hardware knows that what works they have to do. In other words, it is the computer program through which hardware of the computer systems understand how to work. There are several types of software such as application software, system software, and utility software.
Answer:
(B) A single public IP address that it can use for NAT
Explanation:
Because the IPV4 IP protocol is still used today, the number of available IP addresses is limited (only 4,294,967,296 addresses in the world), for this reason, the most correct practice is the assignment of a single public IP to those companies that acquire services from an ISP, with some few exceptional cases of companies that own several.
So that the company's addressing can be executed successfully, the use of NATs is enabled, this allows the translation of network addresses, allowing the company to have as many private networks as necessary and that these can be communicated Correctly with the global network, the Internet, through the public IP of the company.
Not a real memory but it points to physical memory.
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Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}
