Yes I've noticed this. Unfortunately it's up to the user (Asker) to report an answer incorrect.
Answer:
A
Explanation:
The value will be the original stored in the int variables. This is because the method swap(int xp, int yp) accepts xp and yp parameters by value (They are passed by value and not by reference). Consider the implementation below:
public class Agbas {
public static void main(String[] args) {
int xp = 2;
int yp = xp;
swap(xp,yp); //will swap and print the same values
System.out.println(xp+", "+yp); // prints the original in values 2,2
int xp = 2;
int yp = 5;
swap(xp,yp); // will swap and print 5,2
System.out.println(xp+", "+yp); // prints the original in values 2,5
}
public static void swap(int xp, int yp){
int temp = xp;
xp = yp;
yp = temp;
System.out.println(xp+", "+yp);
}
}
Answer:
Option d is the correct answer for the above question
Explanation:
- The above question asked about the result of the above question code, which has the query of two tables and their primary key is matched in the where class.
- The Customer_T table has a primary key "CustomerID" and the Order_T has a foreign key "Customer_ID" and that both are matched in the where clause.
- So the above query fetches that result in which the records match both the table. Hence Option d is the correct answer for the above question while the other is not because another option is not to get by the result of the above query.
Answer:contrast
Explanation:
To make sure it’s easier to read
