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Igoryamba
3 years ago
8

PLEASE HELP POWER POINT:

Computers and Technology
2 answers:
Allushta [10]3 years ago
6 0
18: b format
20: b ctrl + and left mouse button
Nataly [62]3 years ago
5 0

18 is playback, not formatting.

You might be interested in
Write a program that prints the Grade based on the given data. 95-100: A+ 90-94: A 80-89: B+ 70-79: B 60-69: C+ 50-59: C <49
mr Goodwill [35]

Answer:

The program to this question as follows:

Program:

score=int(input("Enter your percentage: ")) #input grade by user

#using conditional statement for match condition  

if 95<=score <= 100: #if value in between 95 to 100

   grade = 'A+' #assign grade

elif 90 <=score <= 94: #elif value in between 90 to 94

   grade = 'A' #assign grade

elif 80 <=score <= 89:  #elif value in between 80 to 89

   grade = 'B+' #assign grade

elif 70 <=score <= 79:  #elif value in between 70 to 79

   grade = 'B' #assign grade

elif 60 <=score <= 69:  #elif value in between 60 to 69

   grade = 'C+' #assign grade

elif 50 <=score <= 59:  #elif value in between 50 to 59

   grade = 'C' #assign grade

elif score<49 :  #elif value is less then 49

   grade = 'F' #assign grade

print (grade) #print grade

Output:

Enter your percentage: 50

C

 Explanation:

In the above python code, a variable "score" is defined, this variable is used for taking value from the user end. In the next step if-elif-else conditional statement is used, this statement is used when a group of statements is given in which one is true. The if block check score value is between 95-100 if this is true it will print A+.

In elif block if the above condition is not true, then this condition will execute, in this block, there are multiple elif block is used that can be described as follows:

  • In the first block, if the value in between 90-94. It will print A.
  • In the second block, if the value in between 80-89. It will print B+.
  • In the third block, if value in between 70-79. It will print B.
  • In the fourth block, if value in between 60-69. It will print C+.
  • In the fifth block, if value in between 50-59. It will print C.
  • In the last, if the value of the score is less then 49. It will print F.
8 0
3 years ago
Using tracking code, google analytics can report on data from which systems?
soldier1979 [14.2K]
The correct answers are:
<span>E-commerce platformsMobile
Applications
Online point-of-sales systems
Source and explanation: https://goo.gl/guJKC9
</span>
6 0
3 years ago
Lisa has had her California real estate license suspended for violations involving mobile homes under the California Business an
yan [13]

Answer:

Both A and B.

Explanation:

In the above statement, there some details of the question is missing that is options.

She has already had its California property license revoked under California Corporation and Occupations Law for breaches regarding mobile homes. So, she possibly she sent a check for mobile home payments to the State of California as well as the check was not honoured and she has participated knowingly in the sale of a mobile home.

7 0
3 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
Please help it's my last question
Yuki888 [10]

Explanation:

here is your answer.. of. different between client / server architecture and peer to peer architecture of the network.

6 0
2 years ago
Read 2 more answers
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