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Sliva [168]
3 years ago
7

Which expression has the same value as m-4 + 1/5-4

Mathematics
2 answers:
frutty [35]3 years ago
7 0
If its m-4 + 1/5-4, it's b
if you meant m^-4 + (1/5)^-4, it should be a
VikaD [51]3 years ago
3 0

Answer:

\frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}+5\times 5\times 5\times 5

m^{-4}+\frac{1}{5^{-4}}

Step-by-step explanation:

Given expression,

m^{-4}+\frac{1}{5^{-4}}

In option a),

\frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}+5\times 5\times 5\times 5

By using product rule of exponent,

\frac{1}{m^{1+1+1+1}}+5^{1+1+1+1}

=\frac{1}{m^4}+5^4

By using a^m=\frac{1}{a^{-m}}

=m^{-4}+\frac{1}{5^{-4}}

Similarly, in option c),

\frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}+4\times 4\times 4\times 4

\frac{1}{m^{1+1+1+1}}+4^{1+1+1+1}

=\frac{1}{m^4}+4^4

=m^{-4}+\frac{1}{4^{-4}}

In option d)

\frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}\times \frac{1}{m}+\frac{1}{5}\times \frac{1}{5}\times \frac{1}{5}\times \frac{1}{5}

\frac{1}{m^{1+1+1+1}}+\frac{1}{5^{1+1+1+1}}

=\frac{1}{m^4}+\frac{1}{5^4}

Hence, option a) and b) are correct.

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