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3 years ago

I need help with this math problem need help please

Mathematics

2 answers:

anyanavicka [17]3 years ago

5 0

If the point is translated 8 units to the left the x-coordinate of the original point is decreased by 8. If the point is translated down 9 units the y-coordinate of the original point is decreased by 9.

So if the original point is (4,6) then the new point is ((4-8), (6-9))=(-4, -3)

The distance between these two points can be found with the Pythagorean Theorem. Because the distance between the two points is equal to the length of the hypotenuse of a right triangle with sides equal to the displacements we made for the transformation.

d^2=8^2+9^2

d^2=64+81

d^2=145

d=√145 units

d≈12.04 units (to the nearest hundredth of a unit)

So the closest measurement that you have to choose from is 12 units.

sergey [27]3 years ago

3 0

Step 1) Plot the points (you do know how to plot, do you?)

Step 2) Take that point and move it 8 squares to left then 9 down

Step 3) You should get (-3,-4). If you didn't let me know. :)

Step 4) ABout how many units are they away from each other?

Step 5) Hint: add the units you needed to move.

Hope this helps. Let me know if it didn't. :)

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Answer:

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Step-by-step explanation:

Given

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So, we have:

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So, we have:

$m = \lim_{h \to 0} \frac{\sqrt{36 + h} - 6}{h}$

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Expand the numerator

$m = \lim_{h \to 0} \frac{36 + h - 36}{h(\sqrt{36 + h} + 6)}$

Collect like terms

$m = \lim_{h \to 0} \frac{36 - 36+ h }{h(\sqrt{36 + h} + 6)}$

$m = \lim_{h \to 0} \frac{h }{h(\sqrt{36 + h} + 6)}$

Cancel out h

$m = \lim_{h \to 0} \frac{1}{\sqrt{36 + h} + 6}$

$h \to 0$ implies that we substitute 0 for h;

So, we have:

$m = \frac{1}{\sqrt{36 + 0} + 6}$

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$m = \frac{1}{6 + 6}$

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<em>Hence, the slope is 1/12</em>

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